3.45x102
Let any number be n:- n3/n3 = n*n*n/n*n*n = 1 And in index form: n3/n3 = n3-3 = n0 = 1
(n - 5) This is how to express 5 less than n mathematically.
If the roots are r1, r2, r3, ... rn, then coeff of x^(n-1) = -(r1+r2+r3+...+rn) and constant coeff = (-1)^n*r1*r2*r3*...*rn.
The binomial expansion is the expanded form of the algebraic expression of the form (a + b)^n.There are slightly different versions of Pascal's triangle, but assuming the first row is "1 1", then for positive integer values of n, the expansion of (a+b)^n uses the nth row of Pascals triangle. If the terms in the nth row are p1, p2, p3, ... p(n+1) then the binomial expansion isp1*a^n + p2*a^(n-1)*b + p3*a^(n-2)*b^2 + ... + pr*a^(n+1-r)*b^(r-1) + ... + pn*a*b^(n-1) + p(n+1)*b^n
'1 : n' is the simplest form of ratios. Equivalent ratios are shown as 1 : n :: m : mn NB Note the use of colons and 'double' colon.
All odd numbers are in the form of (2n + 1) form some integer n. (2n + 1) can be expanded into (n+1)^2 + n^2, which is the difference of two squares.
3.45x102
1 is a rational number, as you can express it as a fraction: 1/1 = 2/2 = 3/3 = 4/4 ... n/n = 1 for finite n.
n>1
1 is a rational number, as you can express it as a fraction: 1/1 = 2/2 = 3/3 = 4/4 ... n/n = 1 for finite n.
D=dance a=awsome n=new c=concentrate e=express
1/6 n(n+1)(n+2)
proportion
The product of two consecutive positive integers can be found by multiplying the smaller integer by the larger integer. If the smaller integer is represented as ( n ), then the larger integer would be ( n + 1 ). Therefore, the product of two consecutive positive integers is ( n \times (n + 1) ).
t(n) = (n+1)2 where n = 1, 2, 3, ...
The standard form of a polynomial in x isa(n)*x^n + a(n-1)*x^(n-1) + ... + a(1)*x + a(0) = 0where the a(i) are constants, for i = 0, 1, 2, ..., n.