Ratios can be written either like this
4/5 or 4:5 both mean 4 out of 5
3.45x102
Let any number be n:- n3/n3 = n*n*n/n*n*n = 1 And in index form: n3/n3 = n3-3 = n0 = 1
(n - 5) This is how to express 5 less than n mathematically.
If the roots are r1, r2, r3, ... rn, then coeff of x^(n-1) = -(r1+r2+r3+...+rn) and constant coeff = (-1)^n*r1*r2*r3*...*rn.
The binomial expansion is the expanded form of the algebraic expression of the form (a + b)^n.There are slightly different versions of Pascal's triangle, but assuming the first row is "1 1", then for positive integer values of n, the expansion of (a+b)^n uses the nth row of Pascals triangle. If the terms in the nth row are p1, p2, p3, ... p(n+1) then the binomial expansion isp1*a^n + p2*a^(n-1)*b + p3*a^(n-2)*b^2 + ... + pr*a^(n+1-r)*b^(r-1) + ... + pn*a*b^(n-1) + p(n+1)*b^n
if you have 3 out of 9 you have to divide first by the GCF which is 3 and after you divide you will get 1 out of 3 and that's your answer!
All odd numbers are in the form of (2n + 1) form some integer n. (2n + 1) can be expanded into (n+1)^2 + n^2, which is the difference of two squares.
3.45x102
To determine the value of ( n ) in a ratio, you need to know the specific ratio being referenced and any additional information or equations that relate to ( n ). Ratios express the relative sizes of two or more quantities, often in the form of ( a:b ). If you provide the specific ratio and any relevant context or values, I can help you find ( n ).
To write 0.489 in standard form, you express it in the form of ( a \times 10^n ), where ( 1 \leq a < 10 ) and ( n ) is an integer. For 0.489, you can rewrite it as ( 4.89 \times 10^{-1} ) since moving the decimal point one place to the right increases the exponent by -1. Thus, the standard form of 0.489 is ( 4.89 \times 10^{-1} ).
1 is a rational number, as you can express it as a fraction: 1/1 = 2/2 = 3/3 = 4/4 ... n/n = 1 for finite n.
n>1
1 is a rational number, as you can express it as a fraction: 1/1 = 2/2 = 3/3 = 4/4 ... n/n = 1 for finite n.
D=dance a=awsome n=new c=concentrate e=express
1/6 n(n+1)(n+2)
t(n) = (n+1)2 where n = 1, 2, 3, ...
proportion