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How do you solve this For a polynomial of degree n express the coefficient of x to the n-1 power and the constant coefficient in terms of the zeros of the polynomial?
Corabecker
If the roots are r1, r2, r3, ... rn, then
coeff of x^(n-1) = -(r1+r2+r3+...+rn)
and
constant coeff = (-1)^n*r1*r2*r3*...*rn.
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Answer thi What is the coefficient of the term of degree 4 in this polynomial?2x5 + 3x4 - x3 + x2 - 12A. 1 B. 2 C. 3 D. 4 s question…
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There is no polynomial below.(Although I'll bet there was one wherever you copied the question from.)
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it is 3. You are doing APEX right?
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a constant polynomial has a degree zero (0).
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Answer thi What is the coefficient of the term of degree 4 in this polynomial?2x5 + 3x4 - x3 + x2 - 12A. 1 B. 2 C. 3 D. 4 s question…
What is the coefficient of the term of degree 7 in the polynomial below?
There is no polynomial below.(Although I'll bet there was one wherever you copied the question from.)
Can two third-degree polynomials be added to produce a second-degree polynomial?
Yes. If the coefficient of the third degree terms in one polynomial are the additive inverses (minus numbers) of the coefficient of the corresponding terms in the second polynomial. Eg: 3x3 + 2x2 + 5 and -3x3 + x - 7 add to give 2x2 + x - 2
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true!
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For a single term, the "degree" refers to the power. The coefficient is the number in front of (to the left of) the x.
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