3x2 - 16x + 5
= 3x2 - x - 15x + 5
= x(3x - 1) - 5(3x -1)
= (3x - 1)(x - 5)
or
I would use the quadratic equation. 3X^2 - 16X + 5 = 0
X = -b +/- sqrt(b^2-4ac)/2a
a = 3
b = -16
c = 5
X = -(-16) +/- sqrt[(-16)^2 - 4(3)(5)]/2(3)
X = 16 +/- sqrt(256 - 60)/6
X = 16 +/-sqrt(196)/6
X = (16 +/- 14)/6
X = 5
X = 1/3
check the easy one
3(5)^2 - 16(5) + 5 = 0
75 - 80 + 5 = 0
0 = 0
easy one checks; you try the 1/3 check
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x3 + 4x2 + 16x + 64 =x2*(x + 4) + 16(x + 4) = (x + 4)*(x2 + 16) which has no further real factors.
You don't. There is no way to factorise it.
16X + 12X all I can see here is factoring out a 4X factor 4X(4 + 3) ---------------
(4x - 3y)(16x^2 + 12xy + 9y^2)
square root -5 minus 14 or - square root -5 minus 14