4x + 3 doesn't factor. It is in its simplest form.
x2 + 4x + 3 =(x + 3) (x + 1)
(2x+3)(2x+4)
16X + 12X all I can see here is factoring out a 4X factor 4X(4 + 3) ---------------
2(x^2 + 2)(x + 3)
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
(4x + 3)(4x + 3) (4x + 3)2
(4x - 3)(4x - 1)
4(x^2 + x + 3)
x2 + 4x + 3 =(x + 3) (x + 1)
It is: 4(x+3)
(4x + 1)(2x + 3)
Re=Write as 16x^(3) + 12x^(2) + 4x Take out the common factor of '4' Hence 4(4x^(3) + 3x^)2) + x) Take out the common factor of 'x' Hence 4x( 4x^(2) + 3x + 1) The answer!!!!!
(2x + 3)(2x - 1)
(x-1)(x-3)
(2x - 3)(2x - 3)
(2x+3)(2x+4)
2(x^2 +2x + 3)