x3 - 2x2 - 4x + 8 = (x2 - 4)(x - 2) = (x + 2)(x - 2)(x - 2)
x(x + 4)(x - 4) or x3 - 16x
64 is the cube of 4 so: x3 + 64 = (x + 4)(x2 - 4x + 16)
x3 + 6x2 - 4x - 24 = (x + 6)(x2 - 4) = (x + 6)(x + 2)(x - 2)
x^3+x^2+4x+4
x3 + 3x2 - 4x -12 x2(x + 3) - 4(x + 3) (x2 - 4)(x+3)
x2(x3 + 1) is the best you can do there.
3 - 3x + x2 - x3 = (1 - x)(x2 + 3)
x3 + x2 - 3x - 3 x(x2 + x - 3) - 3
x2(x + 3)
-x(x2 - 2)(x2 + 3)
x3+27y3 = (x+3y) · (x2-3xy+9y2)