No, 4 is a factor of 64.
V = 64 m3
m6 - 16m3 + 64 = 0 m6 - 8m3 - 8m3 + 64 = 0 m3(m3 - 8) - 8(m3 - 8) = 0 (m3 - 8)2 = 0 (m3 - 2m2 + 2m2 - 4m + 4m - 8)2 = 0 [m2(m-2) + 2m(m-2) + 4(m-2)]2 = 0 [(m2 +2m + 4)(m-2)]2 = 0 So m -2 = 0 or m2 + 2m + 4 = 0 ie m= 2 or m= -1 +/- i*sqrt(3) with each of the three roots being double roots.
64
Just 1.
m3
m3 + 1 = (m + 1)(m2 - m + 1)
The GCF of m2, m3, and m4 is m2.
It can be. 64 is a factor of 128, among others.
No, 3 is not a factor of 64.
No, 4 is a factor of 64.
The Greatest Common Factor (GCF) of 64 and 128 is: 64
V = 64 m3
M6 - 81 = M6 - 92 = (M3 - 9)(M3 + 9) [difference of two squares]
19m^3=19mmm
64 is not a factor of 8.Factor of a number x is always less than or equal to x.
64