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No, 4 is a factor of 64.
V = 64 m3
m6 - 16m3 + 64 = 0 m6 - 8m3 - 8m3 + 64 = 0 m3(m3 - 8) - 8(m3 - 8) = 0 (m3 - 8)2 = 0 (m3 - 2m2 + 2m2 - 4m + 4m - 8)2 = 0 [m2(m-2) + 2m(m-2) + 4(m-2)]2 = 0 [(m2 +2m + 4)(m-2)]2 = 0 So m -2 = 0 or m2 + 2m + 4 = 0 ie m= 2 or m= -1 +/- i*sqrt(3) with each of the three roots being double roots.
64
Just 1.