4x^(2) - 81 First remember the two numbers are both squared numbers. 4 = 2^(2) & 81 = 9^(2) Hence (2x)^(2) - 9^(2) Next remember two squared terms with a negative(-) between them , will factor. Hence (2x - 9)(2x + 9) Note the two different signs. NB Two squared terms with a positive (+) between them does NOT factor. .
well, the square root of 81 is 9, and seven squared is 49, so it wud be 40
81 x 81 = 6561
-9 squared = 81(-9)^2 = (-9) * (-9) = 81
812 = 81 x 81 = 6,561
(9 - 5u)(9 + 5u)
(81 - m2) = (9 - m)(9 + m)
I believe it is prime as you have written it. change the end to + 81 and it factors as (2x - 1)(x-9)(x+9)
9x2 - 6xy + y2 - 81 = (3x - y)2 - 81 = (3x - y - 9)*(3x - y + 9)
(2x - 9)(2x - 9) or (2x - 9)2
Type your answer here... 81
4x^(2) - 81 First remember the two numbers are both squared numbers. 4 = 2^(2) & 81 = 9^(2) Hence (2x)^(2) - 9^(2) Next remember two squared terms with a negative(-) between them , will factor. Hence (2x - 9)(2x + 9) Note the two different signs. NB Two squared terms with a positive (+) between them does NOT factor. .
81 x 2 - 16 = 146
9x2 - 6xy + y2 - 81 = (3x - y)2 - 92 = (3x - y - 9)(3x - y + 9)
78 minus78
79, -79
The answer? There is no "answer" There cannot be an answer because they are all different. In order to make calculations, the variables have to be the same. x squared, xy, y squared are the variables, and none of them match. Therefore your "answer" must look like this: 9x squared - 6xy + y squared - 81. Hope I Helped :D