(x + 3)(x^2 - 3x + 9)
(c + 3)(c^2 - 3c + 9)
t3-1/27
3 cube =27 4 cube =64 5 cube =125 6cube=216 so 3 cubed + 4 cubed + 5 cubed = 6 cubed
2a^3 + 54 can first be factored into 2 (a^3 + 27). This can then be factored out to 2 (a + 3) (a^2 - 3a + 9).
(y + 27)(y^2 - 27y + 729)
2 squared is 4 3 cubed is 27 27 plus 4 is 31
(x + 3)(x^2 - 3x + 9)
(c + 3)(c^2 - 3c + 9)
64 should be between 27 and 125. (1 cubed equals 1. 2 cubed equals 8. 3 cubed equals 27. 4 cubed equals 64. Etc.)
9p + 27 = 9(p + 3)
It is: 3*3*3 = 27
It is: 3*3*3 = 27
How about: 3*3*3 = 27
t3-1/27
True. Three cubed equals twenty-seven
3^3, or 27, is a factor of 108.