(x + 3)(x^2 - 3x + 9)
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t3-1/27
w3+125
x3 + x = x(x2+1)
2(x^2 + 2)(x + 3)
X^3 + 27 = 0 subtract 27 from both sides X^3 = -27 take cubic root of both sides X = -3 (this sentence is true for x = -3) x3 + 27 = 0 the left side is the sum of the cubes, so it is factorable such as: x3 + 33 = 0 (x + 3)(x2 - 3x + 9) = 0