(4x - 1)(x - 5)
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To factor 4x^2 - 21x + 5, we look for two binomials in the form (Ax + B)(Cx + D) that multiply to give 4x^2 - 21x + 5. We can determine the values of A, B, C, and D by examining the factors of 4 and 5. The factored form is then (4x - 1)(x - 5).
3x2-21x+36 =3(x2-7x+12) =3(x-4)(x-3)
(2x+3)/(10x2+21x+9)Factor the quadratic expression in the denominator:(2x+3)/(5x+3)(2x+3)which becomes:1/(5x+3) or (5x+3)-1
2x2 + 21x + 49= 2x2 + 14x + 7x + 49= 2x(x + 7) + 7(x + 7)= (x + 7)(2x + 7)
y = 3x + 21x2 = 3x(1 + 7x)
10x2 + 21x - 10 = 10x2 + 25x - 4x - 10 = 5x(2x + 5) - 2(2x + 5) = (2x + 5)(5x -2)