2a + 5a + 3a = 10a
6b+5a-4b+3a= ? Rearrange it as 5a+3a+6b-4b = 8a+2b
7a + 4 = 5a + 7 7a = 5a + 3 2a = 3 a = 3/2
3a4 - 2a2 + 5a - 10 - 2a4 + 4a2 + 5a - 2 = a4 + 2a2 + 10a - 12 = a4 + (2a - 2)(a + 6)
5a = -5a + 5Add 5a to each side:10a = 5Divide each side by 10:a = 5/10 = 1/2
a + 3a + 5a = 180 9a =180 a = 20
5a-20+2a = 6a-11 5a+2a-6a = 20-11 1a = 9 a = 9
a + b + c = 180 b = 3a c = 5a Substituting the values of b and c into the first equation. a + 3a + 5a = 180 or 9a = 180 so that a = 20 then b = 3a = 3*20 = 60 and c = 5a = 5*20 = 100
5a-20 = -15
5a-20=
5a + 3 + (2a - 2) + a= 5a + 3 + 2a - 2 + a= 8a + 1
5a
so 5a = -20 making a = -4
2a + 5a + 3a = 10a
2a+5a+9a = 16a
(a2 + 5a + 6)/(a - 2) = (a + 2)*(a 3)/(a - 2) which cannot be simplified further. It can, however be written as (a2 - 2a + 7a - 14 + 20)/(a - 2) which is (a + 7) + 20/(a - 2)
The statement is false. 5a +6 = 5a + 30 Subtract 5a from both sides: 6 = 30 and that is plain and simple rubbish!