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Anonymous
Find what you can divide both 6ax and 9a by.
They can both be divided by 3, leaving 2ax and 3a.
These can both be divided by a, leaving 2x and 3.
So 6ax + 9a = 3a (2x + 3)
The factors of 6ax + 9a are 3a and (2x + a)
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12a + 6b + 9a + 14b =(12a + 9a) + (6b + 14b) =21a + 20b
(9a + 2)(9a + 2)
a2+9a+20 = (a+4)(a+5) when factored
9a+21 3(3a+7)