Area = Length * Width = 13 ft * 6 ft = 13*6 sq ft = 78 sq ft
32 square feet. Multiply length by width.
measure length by width = sq ft
Yes. convert to the common unit of measurement (e.g. ft to yd) and then multiply length times width.
Assuming Width <= Length then the width can be any positive value less than sqrt(270) feet = 16.43 feet (approx). Width = 15 ft goes with Length = 270/15 = 18 feet Width = 10 ft with Length = 270/10 = 27 ft Width = 0.0001 ft with Length = 270/0.0001 = 2700000 ft etc.
Length times width.
Length times width. 10x12 room is 120 sq. ft.
1 width times 1 length and divide by 9. Width times length gives you square footage, 9 sq. ft. in 1 sq. yrd.
Length*Width = Area so Width = Area/Length = 40.64 sq ft/12.7 ft = 3.2 ft.
Area = Length * Width = 13 ft * 6 ft = 13*6 sq ft = 78 sq ft
what is the length x width of a rectangle swimming pool that is 13300 sq ft
area = width x length width = area/length width = 925 sq ft/37 ft width = 25 ft
Area = Length * Width 300 sq ft = L ft * W ft So W = 300/L ft
Area = Length*Width so Width = Area/Length = 255/17 ft = 15 feet.
By multiplying its length to its width. Area= length x width
volume_cuboid = length × width × height = 4 ft × 2.3 ft × 5 ft = 46 cu ft surface_area_cuboid = 2 × (length × width + width × height + height × length) = 2 × (4 ft × 2.3 ft + 2.3 ft × 5 ft + 5 ft × 4 ft) = 2 × (9.2 sq ft + 11.5 sq ft + 20 sq ft) = 2 × 40.7 sq ft = 81.4 sq ft
Depends length-25ft width-10ft length - 125ft width - 2ft length - 50ft width- 5ft