Asymptotes occur in places where the equation is not valid E.g the equation (1-2x)/x is not valid when x=0 (otherwise you'd be dividing by zero, which is not allowed). Thus there is a asymptote along the x-axis.
If you have an equation in a similar form to the one above (i.e a/b) , look at the denominator (b) and work out where it is not valid. This is generally the easiest method of finding asymptotes.
Other ways include "trial and error" - subbing in numbers and finding the place where it becomes mathematically impossible to have the equation running along that point.
Sometimes it is easier to sub a few numbers into the equation to begin with, and draw a sketch of where you think it goes. This should highlight areas /how many asymptotes to expect; after that you just have to find out exact locations.
finding vertical asymptotes is easy. lets use the equation y = (2x-2)/((x^2)-2x-3) since its a rational equation, all we have to do to find the vertical asymptotes is find the values at which the denominator would be equal to 0. since this makes it an undefined equation, that is where the asymptotes are. for this equation, -1 and 3 are the answers for the vertical ayspmtotes. the horizontal asymptotes are a lot more tricky. to solve them, simplify the equation if it is in factored form, then divide all terms both in the numerator and denominator with the term with the highest degree. so the horizontal asymptote of this equation is 0.
answer is:Find the function's zeros and vertical asymptotes, and plot them on a number line.Choose test numbers to the left and right of each of these places, and find the value of the function at each test number.Use test numbers to find where the function is positive and where it is negative.Sketch the function's graph, plotting additional points as guides as needed.
You find the equation of a graph by finding an equation with a graph.
Because the two variables cannot be zero voltage = current*resistance if we draw graph current against resistance we would see a exponential graph which means the two variables are inversely proportional but either cannot be zero because voltage is not equal to 0 n.j.p
The answer depends on what you mean by "vertical of the function cosecant". cosec(90) = 1/sin(90) = 1/1 = 1, which is on the graph.
When you graph a tangent function, the asymptotes represent x values 90 and 270.
2
that's simple an equation is settled of asymptotes so if you know the asymptotes... etc etc Need more help? write it
When you plot a function with asymptotes, you know that the graph cannot cross the asymptotes, because the function cannot be valid at the asymptote. (Since that is the point of having an asymptotes - it is a "disconnect" where the function is not valid - e.g when dividing by zero or something equally strange would occur). So if you graph is crossing an asymptote at any point, something's gone wrong.
7/12 and 7/12 is the answer
Press Window and scroll down to Xres. Change it to 2. Then press GRAPH. If the asymptotes still do not appear, increase the Xres number by one until they do. (It cannot go higher than eight.)
Yes, at k*pi radians (k*180 degrees) where k is any integer.
If you are looking at a graph and you want to know if a function is continuous, ask yourself this simple question: Can I trace the graph without lifting my pencil? If the answer is yes, then the function is continuous. That is, there should be no "jumps", "holes", or "asymptotes".
There are some characters missing from the question and, without them, the question makes no sense and so cannot be answered.
They are called asymptotes.
Sketching a graph is drawing an approximation of the graph. The shape of the graph must be correct including the correct number of intercepts with the axes and any asymptotes. You are usually expected to label these. However, you are not required to ensure that the scales on the axes are accurate or other points on the graph are accurately marked.
finding vertical asymptotes is easy. lets use the equation y = (2x-2)/((x^2)-2x-3) since its a rational equation, all we have to do to find the vertical asymptotes is find the values at which the denominator would be equal to 0. since this makes it an undefined equation, that is where the asymptotes are. for this equation, -1 and 3 are the answers for the vertical ayspmtotes. the horizontal asymptotes are a lot more tricky. to solve them, simplify the equation if it is in factored form, then divide all terms both in the numerator and denominator with the term with the highest degree. so the horizontal asymptote of this equation is 0.