The formula for finding a rectangle's perimeter is 2(l+w).
Here, length is given as 12 m & width as 6m. So, the correct answer is
2(l+w)
=2(12+6)
=2 x 18
=36m.
Perimeter is 36 mArea is 72 square m
The C130 Hercules was designed to be a military transport aircraft. Its dimensions originally were 12m in length, 2.7m in height and 3.0m in width. It is powered by four engines.
If you mean area of a rectangle then it is 25 times 12 = 300 square m
Its breadth is also 12m because 12 times 12 = 144 square m
-6
Perimeter is 36 mArea is 72 square m
Perimeter = 12+12+3+3 = 30m
Perimeter=2(l+b) =2*6 =12m
i think that it si 4x3 and it eqals 12
if the perimeter is 12 then the semi perimeter is 6 p=2L+2w 12=2L+2w by division 6=L+w
12m
To find the area of a rectangle, multiply the length times the width- or 6 x 12 in your case.
Assuming that the measures given in the question refer to the lengths of the sides of the rectangle, the answer is 40 metres.
The perimeter of a rectangle is the distance all the way round it.That's lenght (4.5m) + a breadth (1.5m) + another length (4.5m) + another breadth (1.5m) = 12m.Algebraically, the perimeter is 2(l + b), where l is the length and b is the breadth, = 2 x (4.5m + 1.5m) = 2 x 6m = 12m.
Perimeter = sum of all sides Sides = 4.5m, 4.5m, 1.5m, 1.5m Total = 12m
There cannot be a 12m rectangle. A rectangle is a two dimensional object and so there must be two linear measures to describe it. Either there is measure of another length, for example a 12m x 8m rectangle. In that case the question is redundant. Or the 12m is intended as a measure of area and should actually have been 12 SQUARE metres. However, in that case, there are infinitely many possible solutions.
The length of the rectangle in question is 12 meters, and the width of the rectangle is 6 meters.We solve this by knowing that the area of a rectangle is equal to the length (l) times the width (w). That formula looks like this:Arectangle = l x wWe are told that the length is twice the width. Here's that idea in the form of an equation:l = 2wSince the length is twice the width, we can substitute the 2w for the l in the first equation. It looks like this:Arectangle = 2w x wNow we add the fact that the area was given as 72 meters2. and put it all together. It looks like this:72 meters2 = 2w x w72 meters2 = 2w236 meters2 = w2sqrt 36 meters2 = w6 meters = wWe have our width as 6 meters. The length is twice that, or 6 meters x 2 = 12 meters. There are our length and width. Let's check our work.Area = length (12 meters) times width (6 meters) = 12m x 6m = 72 m2Our work checks.