The component of a vector x perpendicular to the vector y is x*y*sin(A) where A is the angle between the two vectors.
Suppose the magnitude of the vector is V and its direction makes an angle A with the x-axis, then the x component is V*Cos(A) and the y component is V*Sin(A)
Two methods can be used for vector addition. (1) Graphically. Place the vectors head-to-tail, without changing their direction or size. (2) Analytically, that is, mathematically. Add the x-component and the y-component separately. The z-component too, if the vectors are in three dimensions.
To find the perpendicular height of a square pyramid, first compute for the volume of the pyramid. Then divide the volume by the area of the base to find pyramid's height.
To find the slope of a perpendicular line, take the negative reciprocal of the slope of the given line. (Flip the top and bottom of the fraction and change the sign.) The slope of 3 can be written as 3/1. The slope of a line that is perpendicular is -1/3.
A square has perpendicular diagonals. They are all the same angle (90 degrees). All sides are the same length. To find area of a square, use the formula A=4s. (Area=4xthe lenghth of the sides.)
Given the vector in angle-radius form? y-component=r sin(theta), x-component=r cos(theta)
You don't. Knowing two of the vector's orthogonal components doesn't tell you what the third one is. It could be absolutely anything.
I think you meant to ask for finding a perpendicular vector, rather than parallel. If that is the case, the cross product of two non-parallel vectors will produce a vector which is perpendicular to both of them, unless they are parallel, which the cross product = 0. (a zero vector)
An easy way to visual this is by drawing a triangle with the vectors. Obviously one vector will be the vertical and another will be perpendicular to that, the horizontal. These two vectors will connect at the ends. Then you connect the other two ends with another vector and that is the resultant. Vector sum, or the square root of the sum of the squares; you use the pythagorem theorem to find the resultant, also the hypotenuse. r2= v12 + v22. The vertical vector squared plus the horizontal squared, you take the root of the sum of the squared vectors and that gives the resultant vector. If the horizontal or vertical vector is negative, then the resultant vector will be negative as well. This is used for any units including velocity, distance, and acceleration.
If you assume the vector is only in two dimensions, you can find the missing y-component with Pythagoras' Theorem: y = square root of (magnitude2 - x2).
Suppose the magnitude of the vector is V and its direction makes an angle A with the x-axis, then the x component is V*Cos(A) and the y component is V*Sin(A)
It's not. Cos(Θ) only gives you the x-component of a vector. In order to find its y-component, you also need to use sin(Θ).
A normal vector is a vector that is perpendicular or orthogonal to another vector. That means the angle between them is 90 degrees which also means their dot product if zero. I will denote (a,b) to mean the vector from (0,0) to (a,b) So let' look at the case of a vector in R2 first. To make it general, call the vector, V=(a,b) and to find a vector perpendicular to v, i.e a normal vector, which we call (c,d) we need ac+bd=0 So say (a,b)=(1,0), then (c,d) could equal (0,1) since their dot product is 0 Now say (a,b)=(1,1) we need c=-d so there are an infinite number of vectors that work, say (2,-2) In fact when we had (1,0) we could have pick the vector (0,100) and it is also normal So there is always an infinite number of vectors normal to any other vector. We use the term normal because the vector is perpendicular to a surface. so now we could find a vector in Rn normal to any other. There is another way to do this using the cross product. Given two vectors in a plane, their cross product is a vector normal to that plane. Which one to use? Depends on the context and sometimes both can be used!
You must find the x and y components of each vector. Then you add up the like x components and the like y components. Using your total x component and total y component you may then apply the pythagorean theorem.
If a vector is given in component form <x1,y1> and <x2,y2>, then you add or subtract the corresponding components. <x1,y1>+<x2,y2>=<x1+x2,y1+y2>
Two methods can be used for vector addition. (1) Graphically. Place the vectors head-to-tail, without changing their direction or size. (2) Analytically, that is, mathematically. Add the x-component and the y-component separately. The z-component too, if the vectors are in three dimensions.
You need to know that the cross product of two vectors is a vector perpendicular to both vectors. It is defined only in 3 space. The formula to find the cross product of vector a (vector a=[a1,a2,a3]) and vector b (vector b=[b1,b2,b3]) is: vector a x vector b = [a2b3-a3b2,a3b1-a1b3,a1b2-a2b1]