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The component of a vector x perpendicular to the vector y is x*y*sin(A) where A is the angle between the two vectors.

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Q: How do you find the component of a vector perpendicular to another vector?
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Related questions

How do you find the components to a vector?

Given the vector in angle-radius form? y-component=r sin(theta), x-component=r cos(theta)


How do you find the y-component of a vector if you are given x-component and z-component?

You don't. Knowing two of the vector's orthogonal components doesn't tell you what the third one is. It could be absolutely anything.


How to you find a vector parallel to two given vectors?

I think you meant to ask for finding a perpendicular vector, rather than parallel. If that is the case, the cross product of two non-parallel vectors will produce a vector which is perpendicular to both of them, unless they are parallel, which the cross product = 0. (a zero vector)


How do you find resultant velocity with perpendicular velocities?

An easy way to visual this is by drawing a triangle with the vectors. Obviously one vector will be the vertical and another will be perpendicular to that, the horizontal. These two vectors will connect at the ends. Then you connect the other two ends with another vector and that is the resultant. Vector sum, or the square root of the sum of the squares; you use the pythagorem theorem to find the resultant, also the hypotenuse. r2= v12 + v22. The vertical vector squared plus the horizontal squared, you take the root of the sum of the squared vectors and that gives the resultant vector. If the horizontal or vertical vector is negative, then the resultant vector will be negative as well. This is used for any units including velocity, distance, and acceleration.


How do you find the vector components only given the magnitude and x-component?

If you assume the vector is only in two dimensions, you can find the missing y-component with Pythagoras' Theorem: y = square root of (magnitude2 - x2).


How do you find the x and y components of a vector?

Suppose the magnitude of the vector is V and its direction makes an angle A with the x-axis, then the x component is V*Cos(A) and the y component is V*Sin(A)


Why only cos theta is used in vector functions?

It's not. Cos(Θ) only gives you the x-component of a vector. In order to find its y-component, you also need to use sin(Θ).


How do you find a normal vector?

A normal vector is a vector that is perpendicular or orthogonal to another vector. That means the angle between them is 90 degrees which also means their dot product if zero. I will denote (a,b) to mean the vector from (0,0) to (a,b) So let' look at the case of a vector in R2 first. To make it general, call the vector, V=(a,b) and to find a vector perpendicular to v, i.e a normal vector, which we call (c,d) we need ac+bd=0 So say (a,b)=(1,0), then (c,d) could equal (0,1) since their dot product is 0 Now say (a,b)=(1,1) we need c=-d so there are an infinite number of vectors that work, say (2,-2) In fact when we had (1,0) we could have pick the vector (0,100) and it is also normal So there is always an infinite number of vectors normal to any other vector. We use the term normal because the vector is perpendicular to a surface. so now we could find a vector in Rn normal to any other. There is another way to do this using the cross product. Given two vectors in a plane, their cross product is a vector normal to that plane. Which one to use? Depends on the context and sometimes both can be used!


What must you do to non-perpendicular vectors before you can use the Pythagorean theorem to calculate the resultant of the vectors?

You must find the x and y components of each vector. Then you add up the like x components and the like y components. Using your total x component and total y component you may then apply the pythagorean theorem.


How do you find the vector sum and vector diffirences of two vector quantities?

If a vector is given in component form <x1,y1> and <x2,y2>, then you add or subtract the corresponding components. <x1,y1>+<x2,y2>=<x1+x2,y1+y2>


How do you find sum of both vector?

Two methods can be used for vector addition. (1) Graphically. Place the vectors head-to-tail, without changing their direction or size. (2) Analytically, that is, mathematically. Add the x-component and the y-component separately. The z-component too, if the vectors are in three dimensions.


How do you do cross products?

You need to know that the cross product of two vectors is a vector perpendicular to both vectors. It is defined only in 3 space. The formula to find the cross product of vector a (vector a=[a1,a2,a3]) and vector b (vector b=[b1,b2,b3]) is: vector a x vector b = [a2b3-a3b2,a3b1-a1b3,a1b2-a2b1]