The component of a vector x perpendicular to the vector y is x*y*sin(A) where A is the angle between the two vectors.
Suppose the magnitude of the vector is V and its direction makes an angle A with the x-axis, then the x component is V*Cos(A) and the y component is V*Sin(A)
Two methods can be used for vector addition. (1) Graphically. Place the vectors head-to-tail, without changing their direction or size. (2) Analytically, that is, mathematically. Add the x-component and the y-component separately. The z-component too, if the vectors are in three dimensions.
To find the perpendicular height of a square pyramid, first compute for the volume of the pyramid. Then divide the volume by the area of the base to find pyramid's height.
To find the resultant vector through the Pythagorean theorem, you first need to break down the vectors into their horizontal and vertical components. Then, square each component, add them together, and take the square root of the sum. This will give you the magnitude of the resultant vector. Lastly, use trigonometry to determine the direction of the resultant vector by finding the angle it makes with one of the axes.
To find the slope of a perpendicular line, take the negative reciprocal of the slope of the given line. (Flip the top and bottom of the fraction and change the sign.) The slope of 3 can be written as 3/1. The slope of a line that is perpendicular is -1/3.
Given the vector in angle-radius form? y-component=r sin(theta), x-component=r cos(theta)
You don't. Knowing two of the vector's orthogonal components doesn't tell you what the third one is. It could be absolutely anything.
To find the magnitude of the resultant vector, you can use the Pythagorean theorem. Simply square the x-component, square the y-component, add them together, and then take the square root of the sum. This will give you the magnitude of the resultant vector.
I think you meant to ask for finding a perpendicular vector, rather than parallel. If that is the case, the cross product of two non-parallel vectors will produce a vector which is perpendicular to both of them, unless they are parallel, which the cross product = 0. (a zero vector)
If you assume the vector is only in two dimensions, you can find the missing y-component with Pythagoras' Theorem: y = square root of (magnitude2 - x2).
The Poynting vector represents the direction and magnitude of electromagnetic energy flow at a specific time and position. To find its x-component, you can use the formula Poynting vector E x B, where E is the electric field and B is the magnetic field. Calculate the cross product of the electric and magnetic fields to determine the x-component of the Poynting vector.
Suppose the magnitude of the vector is V and its direction makes an angle A with the x-axis, then the x component is V*Cos(A) and the y component is V*Sin(A)
The cross product in vector algebra represents a new vector that is perpendicular to the two original vectors being multiplied. It is used to find the direction of a vector resulting from the multiplication of two vectors.
It's not. Cos(Θ) only gives you the x-component of a vector. In order to find its y-component, you also need to use sin(Θ).
To find the resultant velocity from two perpendicular velocities, you can use the Pythagorean theorem. Square each velocity, sum the squares, and then take the square root of the total to find the magnitude of the resultant velocity. The direction of the resultant velocity can be determined using trigonometry, typically with the arctangent function.
A normal vector is a vector that is perpendicular or orthogonal to another vector. That means the angle between them is 90 degrees which also means their dot product if zero. I will denote (a,b) to mean the vector from (0,0) to (a,b) So let' look at the case of a vector in R2 first. To make it general, call the vector, V=(a,b) and to find a vector perpendicular to v, i.e a normal vector, which we call (c,d) we need ac+bd=0 So say (a,b)=(1,0), then (c,d) could equal (0,1) since their dot product is 0 Now say (a,b)=(1,1) we need c=-d so there are an infinite number of vectors that work, say (2,-2) In fact when we had (1,0) we could have pick the vector (0,100) and it is also normal So there is always an infinite number of vectors normal to any other vector. We use the term normal because the vector is perpendicular to a surface. so now we could find a vector in Rn normal to any other. There is another way to do this using the cross product. Given two vectors in a plane, their cross product is a vector normal to that plane. Which one to use? Depends on the context and sometimes both can be used!
You must find the x and y components of each vector. Then you add up the like x components and the like y components. Using your total x component and total y component you may then apply the pythagorean theorem.