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How do you find the meadian?
If You Have Numbers: 2,2,2,5,5,7,7,8,11 You Add All Of The Numbers: 2+2+2+5+5+7+7+8+11=49 Then You Divide (Hint: Count How Much Numbers You Have In The Set Of Numbers) Then Divide By How Much Numbers You Counted: 49 Divided By 9 = 5.4444444 And So On So The Meadian Is 5.4444444 And So On That Is How You Get The Meadian In A Set Of Numbers* * * * * The above answer is totally incorrect. It gives the method for finding the MEAN which is not the MEDIAN. To find the median, put the numbers in ascending order and then find the middle one. If there are an even number of values, find the average (mean) of the middle two. So for the above example, there are 9 numbers so the middle one is the 5th. So the median is the 5th number = 5. f there was another 11, there would be 10 numbers and the median would be the average of the 5th and 6th numbers = (5+7)/2 = 6
F varies jointly as g h and j One set of values is f equals 18 g equals 4 h equals 3 and j equals 5 Find f when g equals 5 h equals 12 and j equals 3?
f = 54
What is the interquartile range of the following set of numbers A 114 B 90 C 83 D 101 E 97 F 142 G 117 H 87 I 72?
42 losers
The sum of two numbers is 36 the first number is three more than twice the second number find the larger number?
25+11=36: Let f and s represent the first and second numbers respectively. The statement of the problem yields two equations: f + s =36 and f = 3 + 2s. Substituting the function given in the second equation for f into the first equation yields 3 + 2s + s = 36, or (subtracting 3 from each side and merging the s terms, 3s = 33 or s = 11. Then f + 11 = 36 (substituting the value for s into the first equation), or f = 25.
The set f of integers greater than or equal to 12?
f = {n : n Î Z, n ≥ 12}
