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How do you find the meadian?
If You Have Numbers: 2,2,2,5,5,7,7,8,11 You Add All Of The Numbers: 2+2+2+5+5+7+7+8+11=49 Then You Divide (Hint: Count How Much Numbers You Have In The Set Of Numbers) Then Divide By How Much Numbers You Counted: 49 Divided By 9 = 5.4444444 And So On So The Meadian Is 5.4444444 And So On That Is How You Get The Meadian In A Set Of Numbers* * * * * The above answer is totally incorrect. It gives the method for finding the MEAN which is not the MEDIAN. To find the median, put the numbers in ascending order and then find the middle one. If there are an even number of values, find the average (mean) of the middle two. So for the above example, there are 9 numbers so the middle one is the 5th. So the median is the 5th number = 5. f there was another 11, there would be 10 numbers and the median would be the average of the 5th and 6th numbers = (5+7)/2 = 6
F varies jointly as g h and j One set of values is f equals 18 g equals 4 h equals 3 and j equals 5 Find f when g equals 5 h equals 12 and j equals 3?
f = 54
What is the interquartile range of the following set of numbers A 114 B 90 C 83 D 101 E 97 F 142 G 117 H 87 I 72?
42 losers
The sum of two numbers is 36 the first number is three more than twice the second number find the larger number?
25+11=36: Let f and s represent the first and second numbers respectively. The statement of the problem yields two equations: f + s =36 and f = 3 + 2s. Substituting the function given in the second equation for f into the first equation yields 3 + 2s + s = 36, or (subtracting 3 from each side and merging the s terms, 3s = 33 or s = 11. Then f + 11 = 36 (substituting the value for s into the first equation), or f = 25.
Explain in your own words the different Asymptotic functions and notations.?
We often want to know a quantity only approximately and not necessarily exactly, just to compare with another quantity. And, in many situations, correct comparison may be possible even with approximate values of the quantities. The advantage of the possibility of correct comparisons through even approximate values may be much less than the times required to find exact values. We will introduce five approximation functions and their notations.The purpose of these asymptotic growth rate functions to be introduced, is to facilitate the recognition of essential character of a complexity function through some simpler functions delivered by these notations. For examples, a complexity function f(n) = 5004 n3 + 83 n2 + 19 n + 408, has essentially same behavior as that of g(n) = n3 as the problem size n becomes larger to larger. But g(n) = n3 is much more comprehensible and its value easier to compute than the function f(n)Enumerate the five well - known approximation functions and how these are pronounced1. The Notation O: Provides asymptotic upper bound for a given function. Let f(x) and g(x) be two functions each from the set of natural numbers or set of positive real numbers to positive real numbers.Then f(x) is said to be O (g(x)) (pronounced as big - oh of g of x) if there exists two positive integers / real number constants C and k such thatF(x) ≤ C g(x) for all x ≥ k2. The Ω Notation: The Ω notation provides an asymptotic lower for a given function.Let f(x) and g(x) be two functions, each from the set of natural numbers or set of positive real numbers to positive real numbers.Then f(x) is said to be Ω (g(x)) (pronounced as big - omega of g of x) if there exists two positive integer / real number constants C and k such that f(x) ≥ C (g(x)) whenever x ≥ k3. The Notation : Provides simultaneously both asymptotic lower bound and asymptotic upper bound for a given function.Let f(x) and g(x) be two functions, each from the set of natural numbers or positive real numbers to positive real numbers. Then f(x) is said to be (g(x)) (pronounced as big - theta of g of x) if, there exists positive constants C1, C2 and k such that C2 g(x) ≤ f(x) ≤ C1g(x) for all x ≥ k.4. The Notation o: The asymptotic upper bound provided by big - oh notation may or may not be tight in the sense that if f(x) = 2x3 + 3x2 + 1. Then for f(x) = O(x3), though there exists C and k such that f(x) ≤ C(x3) for all x ≥ k yet there may also be some values for which the following equality also holdsf(x) = C(x3) for x ≥ k However, if we considerf(x) = O(x4)then there can not exits positive integer C such thatf(x) = C x4 for all x ≥ kThe case of f(x) = O(x4), provides an example for the notation of small - oh.The notation oLet f(x) and g(x) be two functions, each from the set of natural numbers or positive real numbers to positive real numbers.Further, let C > 0 be any number, then f(x) = o (g(x)) (pronounced as little oh of g of x) if there exists natural number k satisfyingf(x) < C g(x) for all x ≥ k ≥ 15. The Notation ω:Again the asymptotic lower bound Ω may or may not be tight. However, the asymptotic bound ω cannot be tight. The definition of ω is as follows;Let f(x) and g(x) be two functions each from the set of natural numbers or the set of positive real numbers to set of positive real numbers.FurtherLet C > 0 be any number, then f(x) = ω (g(x)) if there exists a positive integer k such that f(x) > C h(x) for all x ≥ k
How do you find the meadian?
If You Have Numbers: 2,2,2,5,5,7,7,8,11 You Add All Of The Numbers: 2+2+2+5+5+7+7+8+11=49 Then You Divide (Hint: Count How Much Numbers You Have In The Set Of Numbers) Then Divide By How Much Numbers You Counted: 49 Divided By 9 = 5.4444444 And So On So The Meadian Is 5.4444444 And So On That Is How You Get The Meadian In A Set Of Numbers* * * * * The above answer is totally incorrect. It gives the method for finding the MEAN which is not the MEDIAN. To find the median, put the numbers in ascending order and then find the middle one. If there are an even number of values, find the average (mean) of the middle two. So for the above example, there are 9 numbers so the middle one is the 5th. So the median is the 5th number = 5. f there was another 11, there would be 10 numbers and the median would be the average of the 5th and 6th numbers = (5+7)/2 = 6
What is a sequence whose function is the set of natural numbers?
(f-1)'=2+2x,x is greater than or equal to zero and f'(2)=3,find f'(x)
What are the 6 numbers if the maximum 35 the range is 14 the mode is 21 the median is 30?
There is no simple answer. Suppose the numbers, in non-decreasing order are A, B, C, D, E and F then A = B = 21 25 < C < 30 D = 60 - C D < E < 35 and F = 35. There are, thus, infinitely many possible values for C, and hence for the data set.
The domain of F(x)=logbx is the set of all real numbers. True or False?
False
Is x the numbers that are domains of both f and g in the function fgx?
No. The set of x-values are the domain for only g. This will result in a set of images, which will be g(x). This set of g(x) values are the domain of f.
How do you calculate grouped data percentile?
The formula for calculating median on grouped data is L + I *(50% * N-F)/f L - lower limit of the median group I - group interval N - Number of frequency (total sum of frequencies in each group) F - cumulative freqency for the group before the median group f - frequency of the median group Since median is just the same as the 2nd quartile, we use 0.5 in place of 50% in the formula. We can tweak the formula a little bit to calculate any percentile. For example, if you want to calculate 35th percentile, change the formula to L + I *(35% * N-F)/f which is L + I *(0.35 * N-F)/f. Please note that L,I,F & f should reflect that of the group where the percentile falls. You can find this by these steps: 1) Calculate N * 0.35. Lets say N=50 then 50* 0.35 = 17.5. 2) Using cumulative frequency, identify the group where 17.5 falls. 3) Use L,I,F & f for that particular group in the formula L + I *(0.35 * N-F)/f
How do you find the mean of 6 numbers?
Mean = sum of all numbers divided by number of numbers you summed. Call numbers a, b, c, d, e, f (a+b+c+d+e+f)/6 = mean
What is the domain of f(x)7x plus 11?
The domain can be any subset of the set of all numbers.
Which set of numbers would you use to describe a temperature?
To describe a temperature, you would typically use a set of numbers that includes both degrees and a unit of measurement, such as Celsius (°C) or Fahrenheit (°F). For example, you might say the temperature is 25°C or 77°F. These numbers represent the degree of heat or coldness in a specific environment.
What is the sub set of Fibonacci primes?
Fibonacci primes are Fibonacci numbers that are also prime numbers. The Fibonacci sequence, defined as F(0) = 0, F(1) = 1, and F(n) = F(n-1) + F(n-2) for n ≥ 2, produces a series of numbers. Among these, the Fibonacci primes include numbers like 2, 3, 5, 13, and 89, which are prime and appear within the Fibonacci sequence. Not all Fibonacci numbers are prime, making Fibonacci primes a specific subset of both prime numbers and Fibonacci numbers.
What is the equation for this A set of 7 numbers has a mean of 9 What additional number must be included in this set to create a new set with a mean that is 3 less than the mean of the original set?
Call the specified numbers a, b, c, d, e, f, and g and the unknown number x. From the problem statement, (a + b + c + d + e + f + g)/7 = 9 [from the definition of "mean" of a set of numbers]. Also (a + b + c + d + e + f + g + x)/(7 + 1) = 9 - 3 = 6, or x/8 = 6 - [(a + b + c + d + e + f + g)/8], or x = 48 - (a + b + c + d + e + f + g).
Is the image of an open set under a continuous mapping need not be open?
f(x) = x^{2} is a continuous function on the set R of real numbers, and (-1, 1) is an open set in R, but f(-1, 1) = [0, 1), and [0, 1) is not an open set in R. So, f is not an open function on R.
