25+11=36: Let f and s represent the first and second numbers respectively. The statement of the problem yields two equations: f + s =36 and f = 3 + 2s. Substituting the function given in the second equation for f into the first equation yields 3 + 2s + s = 36, or (subtracting 3 from each side and merging the s terms, 3s = 33 or s = 11. Then f + 11 = 36 (substituting the value for s into the first equation), or f = 25.
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= The sum of two numbers is -42 the first number minus the second number is 52 Find the numbers? =
If we assume all the numbers to the left of the decimal point are the same, we would start by looking at each number after the decimal from left to right. If there is a difference in number at any time, whichever has the highest number is the larger. Example: 0.44567 and 0.44282 In each number the first two numbers after the decimal are the same (4 and 4), but the third is different. The first number has a 5 and the second number a 2, so the first number is larger. Once the first number of difference is established, the remaining numbers to the right have no bearing on which is the larger number.
The third number is 112, the numbers are 86, 86, 112, 172
Let X be one number and Y be the second number So X = 3Y and X + Y = 18 To solve, substitute the value of X from the first equation into the second equation. 3Y + Y = 18 4Y = 18 Y = 4.5 So X = 3*(4.5) = 13.5
Choose any number for the first number. Subtract 10 minus the number you chose to get the second number.