An equivalent fraction is just a multiple of the one that you have (i.e it is the one that you have, scaled up or down). So multiply the fraction that you have until either the numerator or the denominator match the given numerator/denominator of the fraction with the missing number. The number in the corresponding place on the fraction that you multiplied is the missing number.
Yes.
to find a missing number in a division problem you need to cross mulp. then add your diviser
the missing number in the series 1,4,27.----.3125 is 81,35,729,256,115 .Please help to find the missing number.
To find a missing numerator or denominator in a fraction, you can set up a proportion using the known values. For example, if you have the fraction 2/x = 3/6, you can cross multiply to find the missing numerator: 26 = 3x. Solve for x to find the missing denominator. Alternatively, if you have the fraction y/4 = 5/10, you can cross multiply to find the missing numerator: y10 = 54, and then solve for y to find the missing numerator.
An equivalent fraction is just a multiple of the one that you have (i.e it is the one that you have, scaled up or down). So multiply the fraction that you have until either the numerator or the denominator match the given numerator/denominator of the fraction with the missing number. The number in the corresponding place on the fraction that you multiplied is the missing number.
U sex
You can find a missing denominator if you know something that the fraction is equal to. Then you can find the missing denominator through cross multiplication.
3 3/8 =
That really depends on what information is given.
three hundred thousand only
need to find the missing number 8(7+23)=8(7)+8( )
Yes.
The answer depends on what number is missing and what numbers are known!
to find a missing number in a division problem you need to cross mulp. then add your diviser
The question makes no sense: any fraction IS a number. So there is nothing to find!
the missing number in the series 1,4,27.----.3125 is 81,35,729,256,115 .Please help to find the missing number.