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How do you find the reflection of a point that is reflected over the x- axis and then over the x- axis?
Wiki User
∙ 8y ago
It will be where it was, to start with.
Wiki User
∙ 8y ago
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What is the equation when y equals 2x plus 2 is reflected over the y axis?
First let's look at what y=2x+2 looks like. It is the equation of a line with slope 2 and y intercept 2. When we reflect across the y axis, the point (x,y) become (-x,y). Remember that when you reflect across the x axis (x,y) become (x,-y) and when you reflect across the y axis (x,y) becomes (-x,y) So one way to do this problem is algebraically. The slope cannot change values but must change sign with the reflection about the y axis. Let's take a point, not on the y axis, but on the line. (the point (0,2) is the one on the y axis and it would not change). Take (1,4) and note that after reflection the point is (-1,4). So we have a line with point (-1,4) and slope -2. Put this in point slope form and we have y-4=-2(x+1) or y-4=-2x-2 which in slope intercept form is y=-2x+2. The equation of the reflected line is y=-2x+2 So the original line was y=2x+2 and the reflected line is y=-2x+2. The y intercept is the same. Look at a few points. The point (5,12) was on the original line, and (-5,12) is on the reflected line. (2,4) was on the original one and (-2,4) is on the new one. We could have done this all geometrically without the algebra. The line we started with was y=2x+2. If we reflect across the y axis, we cannot change the y intercept, but the slope must become it's negative. The y values remain unchanged, Right away we could write the equation y=-2x+2. This would change the slope to -2 and the y intercept would remain the same, 2. You can also graph the original line on graph paper, reflect it and note the new slope and the y intercept. This would be another way to find the answer. Sometimes we want the value of points when reflected across axes or even arbitrary lines. Matrices are often used for this. The matrix below will transform a point across the y axis. |-1 0x| |0 1y|
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Measure the distance between the point where the line intercepts the Y axis and the origin
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Measure the angle in a plane perpendicular to the axis of rotation, between the position of a fixed point at the start and end of the rotation.
How do you find the y intercept when you are given the coordinates 5 and 4?
Having one given point is not enough. A y-intercept is described as the point of intersection of a function or relation or line and the ordinate axis (or y-axis).Suppose a function intersects the y-axis at (0, 6), then 6 is the value of the y-intercept. Or if the line that passes through (5, 4) is parallel to x-axis, then y-intercept is 4; if it passes through the origin, then y-intercept is 0; if it is perpendicular to x-axis (or parallel to y-axis) there is not an y-intercept.
Find the points on the y - axis whose distance from the point 3 2 and -1 1.5 are in the Ratio of 2 1?
2/3,0.5/3
How do you find the coordinates of a quadrilateral after reflecting it over the y axis?
If the coordinates of a point, before reflection, were (p, q) then after reflection, they will be (-p, q).
What is the answer to Find the coordinates of the reflection B (4 2) is reflected over the y-axis B and rsquo Question 9 options a) (4 -2) b) (-4 2) c) (-4 -2) d) (4 2) Save?
The answer is b.
Can chord is used to find the direction of reflected ray on a concave mirror if rays are parallel to principal axis?
no
How to find a distance between a point and a y-axis?
The answer is the x coordinate of the point.
How do you find the slope with one point?
y/x where y is the distance of point from x axis and x is the distance from y axis
How can you find the line of reflection if you know the images of some points?
Draw a line joining a point and its image and find its midpoint. Repeat for another pair of point and its image. The line joining these midpoints is the line of reflection.
How do you find the data point for an ordered pair?
Finding the data point for an ordered pair is easy to do. The first coordinate marks a place along the X axis, while the second marks a place along the Y axis. Find the first point on the horizontal axis, then move up or down along the vertical axis to reach the exact data point.
What is the equation when y equals 2x plus 2 is reflected over the y axis?
First let's look at what y=2x+2 looks like. It is the equation of a line with slope 2 and y intercept 2. When we reflect across the y axis, the point (x,y) become (-x,y). Remember that when you reflect across the x axis (x,y) become (x,-y) and when you reflect across the y axis (x,y) becomes (-x,y) So one way to do this problem is algebraically. The slope cannot change values but must change sign with the reflection about the y axis. Let's take a point, not on the y axis, but on the line. (the point (0,2) is the one on the y axis and it would not change). Take (1,4) and note that after reflection the point is (-1,4). So we have a line with point (-1,4) and slope -2. Put this in point slope form and we have y-4=-2(x+1) or y-4=-2x-2 which in slope intercept form is y=-2x+2. The equation of the reflected line is y=-2x+2 So the original line was y=2x+2 and the reflected line is y=-2x+2. The y intercept is the same. Look at a few points. The point (5,12) was on the original line, and (-5,12) is on the reflected line. (2,4) was on the original one and (-2,4) is on the new one. We could have done this all geometrically without the algebra. The line we started with was y=2x+2. If we reflect across the y axis, we cannot change the y intercept, but the slope must become it's negative. The y values remain unchanged, Right away we could write the equation y=-2x+2. This would change the slope to -2 and the y intercept would remain the same, 2. You can also graph the original line on graph paper, reflect it and note the new slope and the y intercept. This would be another way to find the answer. Sometimes we want the value of points when reflected across axes or even arbitrary lines. Matrices are often used for this. The matrix below will transform a point across the y axis. |-1 0x| |0 1y|
Do find the x- and y-coordinates of any point on the xy-plane.?
To find the x-coordinate of a point on the xy-plane, you look at the horizontal distance of the point from the y-axis. The y-coordinate of a point on the xy-plane is the vertical distance of the point from the x-axis.
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by ploting the temperature on the y axis verses time on the x axis
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What is the value of x, to the nearest degree? 1 point Captionless Image
How come when you look in the mirrior you get different reflection sometimes in skinny average or fat?
Your reflection is based on the shape the mirror is.Example:If the mirror was bent outwards the reflected image would appear wider.If the mirror was bent inwards the reflected image would appear thinner.Usually you can commonly find mirrors like these in fun houses, and can be found in various shapes such as cones etc.
