You have to put a line of best fit onto the graph and find where that line crosses the y-axis.
Draw a line of best fit through the plotted points which will give the y intercept. Draw a right angle triangle under the line which will be the triangles hypotenuse. Divide the vertical units of the triangle by the horizontal units which will give the value of the slope.
Plot the y-axis, which is the b in the y=mx+b in the slope intercept equation. Then, you put your slope and plot the line.
The x is the domain, and the y is the range. (:
X axis is across and Y axis is down
You have to put a line of best fit onto the graph and find where that line crosses the y-axis.
You do not have to plot it first but it is a point whose location is sometimes easy to find.
Draw a line of best fit through the plotted points which will give the y intercept. Draw a right angle triangle under the line which will be the triangles hypotenuse. Divide the vertical units of the triangle by the horizontal units which will give the value of the slope.
To find the Y-intercept, plug 0 in for X, so you have 0+Y=-3, or Y=-3. Therefore, your Y-intercept is at the point (0,-3). You do the same thing to find the X-intercept, only reversed. X+0=-3, so X=-3. This intercept is at (-3,0).
You create a grid with the x and y axiis (pardon spelling) and place a point where the values for x and y intercept. Consider the point (5, -3). On the x-axis you move 5 to the right, and for y you move 3 down.
by eating a bana and yes
Dependent variable
no
solve the x and you find the y
Plot the y-axis, which is the b in the y=mx+b in the slope intercept equation. Then, you put your slope and plot the line.
The x is the domain, and the y is the range. (:
To find the y intercept put zero in for x and solve. To find the x intercept put zero in for y and solve. (0,8) and (-8,0)