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I am assuming a right-angled triangle here, or the question has no answer.

From Pythagoras's formula, (a^2+b^2) = c^2,

where a and b are the lengths of the two shorter edges that form the right-angle, and c is the length of the hypotenuse.

Let a and c be known. Then b is the square root of (c^2-a^2).

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Q: How do you find the second leg to a triangle when the hypotenuse and first leg are known?
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