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In a right triangle, the sine of the angle is equal to the

(leg opposite the angle) divided by the (hypotenuse).

It's well known that the hypotenuse is always the longest side in the right triangle,

so this division can never come out to be more than ' 1 '.

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15y ago

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Is the sine of an acute angle is greater that 1?

No. The sine of an acute angle is less than 1. An acute angle is less than 90 degrees. The sine of 0 degrees is 0, and the sine of 90 degrees is +1. So the sines of the angles between 0 degrees and 90 degrees are less than 1.


Can the co-secant of an angle be less than 1?

No, the co-secant (csc) of an angle cannot be less than 1 or greater than -1. This is because the co-secant is defined as the reciprocal of the sine function (csc(θ) = 1/sin(θ)). Since the sine of an angle ranges from -1 to 1, the co-secant will either be greater than or equal to 1 when sine is positive or less than or equal to -1 when sine is negative.


Why are the sine and the cosine of an acute angle always less than 1?

Well, the easiest way to go at it is simply to remember thatthe sine and cosine of any angle are always less than 1 .


Is it possible for the sine of an angle to be greater than 1?

no - nor less than minus 1.


Why sinθ value is less then and equal to one?

If you look at the definition of the sine function in a triangle, you'll discover that the maximum possible value of the sine function is ' 1 ' and the minimum possible value is ' -1 '. There's no angle that can have a sine greater than ' 1 ' or less than ' -1 '. So the absolute value of the sine of anything is always ' 1 ' or less.


Is sine greater than one?

No angle has a sine function greater than 1.


Why sine of an acute angle cannot be greater than 1?

You can only find the inverse of sine for number less than or greater than 1. An improper fraction is not acceptable either because the ratio is opposite over hypotenuse. The hypotenuse will always be the longest, so there you go.


What is the sine of angle of incidence divided by the sine of angle of refraction of equal optical density?

It is 1.


Why are the sine and cosine of an angle always less than 1?

Since the hypotenuse (denominator) is always greater than the opposite or adjacent side (numerator), the ratio will always be smaller than one.


What are the limitations of sine bar?

1 it can not used when the angle more than 45 degrees.....


Why is the sine and cosine of a number no less than -1 and no greater than 1?

The sine of an angle x is defined as the ratio of the opposing side to the hypotenuse, in a right triangle having x as one of its acute angles. If it was greater than 1, it would mean the opposing side was longer than the hypotenuse. Try to draw a right triangle with one of the sides longer than the diagonal. You'll notice it's impossible. So the sine cannot be greater than 1. Fitting the triangle into a circle of radius 1, such that the angle x is located at the origin and the hypotenuse is a radius of the circle, you can define "sine of x" for any angle. Since the triangle may end up flipped in any direction, including the negative x and y axis, it turns out that the sine of any number is between -1 and +1. The cosine is simply the sine of the complementary angle (90 - x). So it must also be contained between -1 and +1.


Which trigonometric functions always have values less than 1?

The sine and the cosine are always less than one.