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There is no easy way to do this one. Even if you were to use the half angle formula to get from 30° to 15° to 7.5°, the computations require the square roots of decimals that get difficult quickly.

This is one time that looking it up or using a calculator to find that it is 0.938 is the only reasonable way.

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Q: How do you find the sin of 7.5 degrees?
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Related questions

If angle A is 60 degrees angle B is 45 degrees angle C is 75 degrees and the length of side AC is 10 units then what is the length of side AB?

This problem can be solved using the Sine Rule :a/sin A = b/sin B = c/sin C 10/sin 45 = AB/sin 75 : AB = 10sin 75 ÷ sin 45 = 13.66 units (2dp)


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How do you construct a triangle with perimeter 150 mm and a base angle 75 degrees and 30 degrees?

Perhaps you can ask the angel to shed some divine light on the question! Suppose the base is BC, with angle B = 75 degrees angle C = 30 degrees then that angle A = 180 - (75+30) = 75 degrees. Suppose the side opposite angle A is of length a mm, the side opposite angle B is b mm and the side opposite angle C is c mm. Then by the sine rule a/sin(A) = b/(sin(B) = c/sin(C) This gives b = a*sin(B)/sin(A) and c = a*sin(C)/sin(A) Therefore, perimeter = 150 mm = a+b+c = a/sin(A) + a*sin(B)/sin(A) + a*sin(C)/sin(A) so 150 = a*{1/sin(A) + sin(B)/sin(A) + sin(C)/sin(A)} or 150 = a{x} where every term for x is known. This equation can be solved for a. So draw the base of length a. At one end, draw an angle of 75 degrees, at the other one of 30 degrees and that is it!


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Sin(285) is a number, not an angle. The reference angle for 285 degrees is 285-360 = -75 degrees.


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sin 300 = -sin 60 = -sqrt(3)/2 you can get this because using the unit circle.


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