Use the Newton-Raphson method.
Let f(x) = x2 - 350
and let f'(x) = 2*x
Then start with any guess, x0.
The next estimate is x1 = x0 - f(x0)/f'(x0).
Continue iterations with xn+1 = xn - f(xn)/f'(xn).
If you start with x0 = 15 (quite a long way off, given that 152 is only 225), x2 is accurate to 6 decimal places (error = 8 in 10 million) and x3 to 13 dp (2 in 100 trillion).
18.708286933869706927918743661583
Do the addition, get the answer and then find its square root!
To find the square root of a number you multiply that number by it self twice.(example) the square root of 9 ? the square root of nine is 81 as 9X9=81. square root of 4 ? th square root of is 16 as 4X4=16.
What I do is find the square root of that number and then find the square root of the answer. Example: 1,296. Square root of 1,296, which can be done easily on most calculators: 36 Square root of 36: 6 Your answer is 6 If you want to check up on that, go ahead, but 6x6x6x6=1,296
Find ab
Yes. The square root of 350 is ± 18.708287 which can be simplified (rounded) to ± 18.7
18.708286933869706927918743661583
18.708
find the square root of the numerator and the square root of the denominator
350.0
5(key)14
Press the square root button on your calculator.
Find the square root of each of its components, and muliply them together. For example, 36x8 the square root of 36 is 6 the square root of x8 is x4 so the square root of 36x8 is 6x4
Do the addition, get the answer and then find its square root!
The square root of 289 is ± 17.
The square root of 1225 is 35.
The square root of 8649 is 93.