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The answer will depend on what c represents. Furthermore, there probably is no value of c such that each expression is a perfect square - you will need different values of c for different trinomials.

The answer will depend on what c represents. Furthermore, there probably is no value of c such that each expression is a perfect square - you will need different values of c for different trinomials.

The answer will depend on what c represents. Furthermore, there probably is no value of c such that each expression is a perfect square - you will need different values of c for different trinomials.

The answer will depend on what c represents. Furthermore, there probably is no value of c such that each expression is a perfect square - you will need different values of c for different trinomials.

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The answer will depend on what c represents. Furthermore, there probably is no value of c such that each expression is a perfect square - you will need different values of c for different trinomials.

Q: How do you find the value of c such that each expression that is a perfect square trinomial?

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What value, in place of the question mark, makes the polynomial below a perfect square trinomial?x2 + 12x+ ?

64

x2 + 22x + 121 to get this divide 22 by 2... then square the answer you get from that 22/2 = 11 112 = 121

Under remarks idicate whether the expression is a perfect square or not

The first term must have an x value raised to an even root, such as x^2 or x^4. The middle term (if a trinomial) must be able to be made by adding together the factors of the coefficients of first and last terms. For example, x^2 +4x +4 can be factored into (x+2) x (x+2), or (x+2)^2

Related questions

What value, in place of the question mark, makes the polynomial below a perfect square trinomial?x2 + 12x+ ?

81.

The answer will depend on what c is!If the trinomial is ax^2 + bx + c then the required value of c is (b^2)/(4a)

64

16 does that.

-12

144

-26

(b/2)^2= 64

Consider this expression: x2-5x+6 And you know that it is a perfect square trinomial. Therefore, you also know that there will be two parenthetical expressions that, when multiplied, will yield x2-5x+6. Keep this in mind throughout the process. Start with the "skeleton". Draw your parentheses. ( )( ) Take the square root of the first number in the expression. In this case, x2. (x )(x ) So now you're all set with the first value in the expression. Once you're sure that the square root is correct, you don't need to go back. ***(This is only true as long as there is no numerical value in front of the variable) Next, think of numbers that, when added, will equal the middle value and that, when multiplied, will equal the third value. In this case, numbers that equal -5 when added, and 6 when multiplied. (You don't need to worry about the variable for the middle value. It does make its way into the unsimplified expression). -2 and -3 are the values So insert the values in the expression. (x-2)(x-3) Multiply the expression out to check the simplification And done!

48

There are infinitely many possible answers: c = Â±4x + 33

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