95x?d/dx(au)=au*ln(a)*d/dx(u)d/dx(95x)=95x*ln(9)*d/dx(5x)-The derivative of 5x is:d/dx(cu)=c*du/dx where c is a constantd/dx(5x)=5*d/dx(x)d/dx(95x)=95x*ln(9)*(5*d/dx(x))-The derivative of x is:d/dx(x)=1x1-1d/dx(x)=1*x0d/dx(x)=1*(1)d/dx(x)=1d/dx(95x)=95x*ln(9)*(5*1)d/dx(95x)=95x*ln(9)*(5)-95x can simplify to (95)x, which equals 59049x.-ln(9) can simplify to ln(32), so you can take out the exponent to have 2ln(3).d/dx(95x)=59049x*2ln(3)*(5)d/dx(95x)=10*59049x*ln(3)
Do not write an equation in words!!! What does x mean in 10y = 5x + 95x? It is a place holder for a number. Any number.
95x 69 is equal to 6,555.
95x is the same as 95x1, so multiply the 95 and the 1 and reduce the 1 by 1 and you get 95x0. x0 = 1 so your answer is 95.
y=.95x
95x.98mmx46
3x+y=-1 y=-1-3x5x-y=9 5x-(-1-3x)=95x+1+3x=98x=8x=1y=-1-3(1)y=-4(1,-4)
f =95c + 32f =95X 10 + 32=50
950
1(95-x)=70 95x=70 x 25x
3x + 5x + 10 = 0a = 3, b = 5, c = 10D = b - 4ac = 25 - 120 = -95Since D < 0, we have two conjugate complex roots.√D = √-95 = i√95x = (- b ± √D)/2ax = -5/6 + [(√95)/6]i or x = -5/6 -[(√95)/6]i
25x?d/dx(au)=au*ln(a)*d/dx(u)d/dx(25x)=25x*ln(2)*d/dx(5x)-The derivative of 5x is:d/dx(cu)=c*du/dx where c is a constantd/dx(5x)=5*d/dx(x)d/dx(25x)=95x*ln(2)*(5*d/dx(x))-The derivative of x is:d/dx(x)=1x1-1d/dx(x)=1*x0d/dx(x)=1*(1)d/dx(x)=1d/dx(25x)=25x*ln(2)*(5*1)d/dx(25x)=25x*ln(2)*(5)-25x can simplify to (25)x, which equals 32x.d/dx(95x)=32x*ln(2)*(5)