3x + 5x + 10 = 0
a = 3, b = 5, c = 10
D = b - 4ac = 25 - 120 = -95
Since D < 0, we have two conjugate complex roots.
√D = √-95 = i√95
x = (- b ± √D)/2a
x = -5/6 + [(√95)/6]i or x = -5/6 -[(√95)/6]i
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Yes, it crosses at (0.23,0) and (1.43,0).
5x+2=x+10 5x-x=10-2 4x=8 x=2
5x+2=2x-10 x=-4
4x - 10 + 5x = 719x = 81x = 9
240-10=5x 5x=230 230/5=46 x=46