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3x + 5x + 10 = 0
a = 3, b = 5, c = 10

D = b - 4ac = 25 - 120 = -95
Since D < 0, we have two conjugate complex roots.

√D = √-95 = i√95

x = (- b ± √D)/2a

x = -5/6 + [(√95)/6]i or x = -5/6 -[(√95)/6]i

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Q: 3x2 plus 5x plus 10 equals 0?
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