y = ax2 + bx + c if it opens up or down,
or x = ay2 + by + c if it is opens to the left or right,
where a, b, and c are constants.
The x-value for the vertex is -(b/2a). You can use this x-value to solve for the y-value by substituting the x value in the original quadratic equation.
Solution 2Put the parabola's equation into this form:y - k = 4p(x - h)2
or x - h = 4p(y - k)2
You just need to simplify the equation until it looks like this. The vertex is located at the coordinates (h,k). (p is for the focus, but that isn't important as long as you know h and k.)
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To find the value of a in a parabola opening up or down subtract the y-value of the parabola at the vertex from the y-value of the point on the parabola that is one unit to the right of the vertex.
The vertex would be the point where both sides of the parabola meet.
the vertex of a parabola is the 2 x-intercepts times-ed and then divided by two (if there is only 1 x-intercept then that is the vertex)
-2
A parabola is NOT a point, it is the whole curve.