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Solution 1Start by putting the parabola's equation into the form

y = ax2 + bx + c if it opens up or down,

or x = ay2 + by + c if it is opens to the left or right,

where a, b, and c are constants.

The x-value for the vertex is -(b/2a). You can use this x-value to solve for the y-value by substituting the x value in the original quadratic equation.

Solution 2Put the parabola's equation into this form:

y - k = 4p(x - h)2

or x - h = 4p(y - k)2

You just need to simplify the equation until it looks like this. The vertex is located at the coordinates (h,k). (p is for the focus, but that isn't important as long as you know h and k.)

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Q: How do you find the vertex of a parabola?
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To find the value of a in a parabola opening up or down subtract the y-value of the parabola at the vertex from the y-value of the point on the parabola that is one unit to the of the vertex?

To find the value of a in a parabola opening up or down subtract the y-value of the parabola at the vertex from the y-value of the point on the parabola that is one unit to the right of the vertex.


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To find the value of a in a parabola opening left or right subtract the x value of the parabola at the vertex from the x value of the point on the parabola that is one unit the vertex?

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What the the vertex of a parabola?

The vertex would be the point where both sides of the parabola meet.


How do you graph parabola given its vertex?

The vertex of a parabola doe not provide enough information to graph anything - other than the vertex!


What is the relationship of a vertex to a parabola?

The vertex is either the minimum (very bottom) or maximum (very top) of a parabola.


What is the vertex of a parabola?

the vertex of a parabola is the 2 x-intercepts times-ed and then divided by two (if there is only 1 x-intercept then that is the vertex)


The is the extreme point of a parabola and is located halfway between the focus and directrix?

The vertex -- the closest point on the parabola to the directrix.


Is knowing the coordinates of the vertex of a parabola enough to determine the domain and range?

i think that the range and the domain of a parabola is the coordinates of the vertex


How do you find the vertex of the parabola y equals -4x2 - 16x - 11?

You would convert it to vertex form by completing the square. You can also find the optimum value as optimum value and vertex are the same.


A parabola that opens upward?

A parabola that opens upward is a U-shaped curve where the vertex is the lowest point on the graph. It can be represented by the general equation y = ax^2 + bx + c, where a is a positive number. The axis of symmetry is a vertical line passing through the vertex, and the parabola is symmetric with respect to this line. The focus of the parabola lies on the axis of symmetry and is equidistant from the vertex and the directrix, which is a horizontal line parallel to the x-axis.


What do you call the maximum or the minimum of a parabola?

A parabola's maximum or minimum is its vertex.