It depends on what country you are talking about.
The largest 5 digit number is 99999. If this is divided by 11 it leaves a remainder of 9. Therefore the largest 5 digit number divisible by 11 is 99999 - 9 = 99990.
The smallest 2 digit whole number is 10 The smallest 2 digit odd whole number is 11
Yes- A remainder can be any number less than the dividend (the number by which the divisor is divided). An example of a 2 digit number is: 131/11=11 remainder 10.
10010
11's of quintillion's
There are about 10-11 digits in a number
47 Impossible problem!
No.
1001 / 11 = 91 1001 is the smallest 4-digit number that 11 divides equally into.
The largest 5 digit number is 99999. If this is divided by 11 it leaves a remainder of 9. Therefore the largest 5 digit number divisible by 11 is 99999 - 9 = 99990.
11 is the smallest two-digit prime number.
11
The first two-digit prime number is 11.
least two-digit composite number = 11
The least 2-digit prime number is 11. Thus, 11 squared is 121.
385. 385 = 5 x 11 x 7 3 + 8 + 5 = 16
74