I cannot see a way. The only way I can think to get an odd number is saying 2/2 is 1. But then 2x2x2 is 8, 8+1 is only 9. If you could join 2s, then you would only need 4. 22/2 is 11, +2 is 13
To get 13 using only five two's, you can use the following mathematical expression: (2 + 2) * (2 + 2) + 2 = 13. This equation breaks down as follows: first, you add two twos together to get 4. Then, you multiply that by another set of two twos to get 8. Finally, you add the remaining two to get 13.
4! - 44/4 = 24 - 11 = 13
Well, isn't that a happy little math problem! To make 13 with 5 twos, you can add 2 + 2 + 2 + 2 + 5. Remember, there are many ways to approach a problem, just like there are many ways to paint a beautiful landscape. Just have fun and enjoy the process!
[(4*4)+(4*4)+(4*4)+4] / 4 = 13
4444=5...? using the basic arithmetic operations like +,*,-,/. but use only once each these symbols try it
13, 26, 39, 52, 65.
23 + 2 19 + 3 + 3 17 + 5 + 3 17 and 4 twos 17, 2 threes and 2 twos 13 + 7 + 5 13 and 6 twos 13 and 4 threes 11 and 2 sevens 11 and 7 twos and a bunch more up to 10 twos and 5 11 twos and 3
The factors of 34 are 1, 2, 17, 34 To get to 13 you could use 13 ones or 6 twos and 1 one or some other combination of ones and twos.
There are a few options for listing five prime numbers using the digits zero to nine only once:2, 3, 5, 7, 8649012, 5, 13, 647, 809
No, there are only five atoms in freon-13
(4x4)+(4/4)-4 The above uses five 4's. An answer, using factorials, and only four is: (4!+4-sqrt(4))/sqrt(4)
Five
13
Only if you subtract three.
8 plus 1 , minus 5, plus 7 + 13
im only 13
4! - 44/4 = 24 - 11 = 13
No. There are only five. Avery, Katani, Isabel, Charlotte and Maeve.