Q: How do you get 1 using 2 3 8 9?

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Using symbol "^" for power. 2^(-3) is 1 / (2^3). 2^3 means 2x2x2.

9 - 1 = 8 2 + 1 = 3 8 x 3 = 24

You do5!/(5+5+5)=8!=factorialfactorial e.g 5!=5*4*3*2*1 or 3!=3*2*1

(8)^1/3 + (8)^1/3 + (8)^1/3 = 2+2+2 = 6.

1 over 2 is 0.5 3 over 8 is 0.375 1 over 2 is bigger Edit: yes 1/2 is greater 1/2 is half (0.5) 3/8 is less than half (0.375) you can also find it by using fractions 1/2 > 3/8 4/8 > 3/8 This question was answered by someone else who must have forgotten to send it off.

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2 - 1 = 1 1 x 3 = 3 3 x 8 = 24

Using symbol "^" for power. 2^(-3) is 1 / (2^3). 2^3 means 2x2x2.

1 + (2 + 5)(16 + 8)/3 (1 + 2) - (1 - 6)

9 - 1 = 8 2 + 1 = 3 8 x 3 = 24

8+8+3+3+2x1=24

4 + 3 + 2 - 1 = 8

3*(2*4 + 1) = 3*(8 + 1) = 3*9 = 27

You have 8 numbers, and you are choosing 3. This is written as 8c3 and is computed like this: [8!] / [ (3!) (8-3!)] = 8! / (3! * 5!) = (8*7*6*5*4*3*2*1) / (3*2*1 * 5*4*3*2*1) Canceling out, you get (8*7*6)/(3*2*1) = 8*7 = 56 ■

You do5!/(5+5+5)=8!=factorialfactorial e.g 5!=5*4*3*2*1 or 3!=3*2*1

Using correct order of operations, 8*3+2=26.

It is: 6*(2+3-1)+80 = 25

1 over 2 is 0.5 3 over 8 is 0.375 1 over 2 is bigger Edit: yes 1/2 is greater 1/2 is half (0.5) 3/8 is less than half (0.375) you can also find it by using fractions 1/2 > 3/8 4/8 > 3/8 This question was answered by someone else who must have forgotten to send it off.