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N squared is 25 more than n So what is n?
n2 = n+25 n2-n-25 = 0 Using the quadratic equation formula gives n a positive value of (1+the square root of 101) over 2 which is about 5.524937811 5.5249378112 = 30.52493782 which is nearly correct.
What are the possible values of k in the quadratic equation x squared plus 5kx plus 2k equals 0 which has equal real roots?
Using the discriminant formula for a quadratic equation k has a value of 8/25 or maybe 0.
What is the point of intersection of the line y equals 2x plus 5 over 4 with the curve y squared equals 10x?
Point of intersection: (5/8, 5/2) Square both sides of the first equation and merge it with the second equation to form a quadratic equation:- 4x2-5x+25/16 = 0 Solving the above using the quadratic equation formula gives x as having two poitive roots of 5/8 and substituting this into the linear equation gives y a value of 5/2.
What quadratic equation is the answer for -5?
x2 + 10x + 25 = 0
What is the value for a makes the equation true 5aa?
To solve the equation (5a = 0), we can set the equation equal to zero, which gives us (5a = 0). Dividing both sides by 5, we find that (a = 0). Therefore, the value for (a) that makes the equation true is (0).
N squared is 25 more than n So what is n?
n2 = n+25 n2-n-25 = 0 Using the quadratic equation formula gives n a positive value of (1+the square root of 101) over 2 which is about 5.524937811 5.5249378112 = 30.52493782 which is nearly correct.
What are the possible values of k in the quadratic equation x squared plus 5kx plus 2k equals 0 which has equal real roots?
Using the discriminant formula for a quadratic equation k has a value of 8/25 or maybe 0.
What is the point of intersection of the line y equals 2x plus 5 over 4 with the curve y squared equals 10x?
Point of intersection: (5/8, 5/2) Square both sides of the first equation and merge it with the second equation to form a quadratic equation:- 4x2-5x+25/16 = 0 Solving the above using the quadratic equation formula gives x as having two poitive roots of 5/8 and substituting this into the linear equation gives y a value of 5/2.
What quadratic equation is the answer for -5?
x2 + 10x + 25 = 0
What is the value for a makes the equation true 5aa?
To solve the equation (5a = 0), we can set the equation equal to zero, which gives us (5a = 0). Dividing both sides by 5, we find that (a = 0). Therefore, the value for (a) that makes the equation true is (0).
What are the solutions to the equation of 2x squared plus 5x -k equals 0 showing work?
You can use the quadratic equation for this one. Set a = 2, b = 5, c = -k.Another Answer:-Using the discriminant of b^2-4ac = 025-4(-2k) = 0 => 25+8k = 0 => k = -25/8 or -3.125So: 2x^2+5x-(-3.125) = 0Using the quadratic equation formula: x has equal values of -5/4 or - 1.25
What is the rate of change in the equation x equal 9?
0. Differentiation of a constant gives f'(x)=0.
How do you solve v2 - 25?
-23
How do you solve for x X2 plus 3x plus 1 equals 0?
x2+3x+1 = 0 Using the quadratic equation formula gives you: (x+2.618033989)(x+0.3819660113) = 0 So: x = -2.618033989 or x = -0.3819660113
What is the x-intercept of4x - y2?
To find the x-intercept of the equation (4x - y^2 = 0), set (y = 0). Substituting this into the equation gives (4x = 0), which simplifies to (x = 0). Therefore, the x-intercept is at the point ((0, 0)).
Is (0-2) a solution of 2x-5y10?
To determine if the point (0, -2) is a solution of the equation (2x - 5y = 10), we can substitute (x = 0) and (y = -2) into the equation. This gives us (2(0) - 5(-2) = 0 + 10 = 10), which is true. Therefore, (0, -2) is indeed a solution of the equation.
What is the y-intercept in the linear equation y equals 6x?
In the linear equation ( y = 6x ), the y-intercept is the point where the line crosses the y-axis. This occurs when ( x = 0 ). Substituting ( x = 0 ) into the equation gives ( y = 6(0) = 0 ). Therefore, the y-intercept is at the point (0, 0).
