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N squared is 25 more than n So what is n?
n2 = n+25 n2-n-25 = 0 Using the quadratic equation formula gives n a positive value of (1+the square root of 101) over 2 which is about 5.524937811 5.5249378112 = 30.52493782 which is nearly correct.
What are the possible values of k in the quadratic equation x squared plus 5kx plus 2k equals 0 which has equal real roots?
Using the discriminant formula for a quadratic equation k has a value of 8/25 or maybe 0.
What is the point of intersection of the line y equals 2x plus 5 over 4 with the curve y squared equals 10x?
Point of intersection: (5/8, 5/2) Square both sides of the first equation and merge it with the second equation to form a quadratic equation:- 4x2-5x+25/16 = 0 Solving the above using the quadratic equation formula gives x as having two poitive roots of 5/8 and substituting this into the linear equation gives y a value of 5/2.
What quadratic equation is the answer for -5?
x2 + 10x + 25 = 0
Simplify 2t squared plus 8t plus 5 equals 0?
2t2+8t+5 = 0 The expression in this quadratic equation is not so simple to factorise because 5 is a prime number which has only two factors (itself and one) but we can get a near enough solution by using the quadratic equation formula. Using the quadratic equation formula gives the solution as: t = - 0.7752551286 or t = - 3.224744871
N squared is 25 more than n So what is n?
n2 = n+25 n2-n-25 = 0 Using the quadratic equation formula gives n a positive value of (1+the square root of 101) over 2 which is about 5.524937811 5.5249378112 = 30.52493782 which is nearly correct.
What are the possible values of k in the quadratic equation x squared plus 5kx plus 2k equals 0 which has equal real roots?
Using the discriminant formula for a quadratic equation k has a value of 8/25 or maybe 0.
What is the point of intersection of the line y equals 2x plus 5 over 4 with the curve y squared equals 10x?
Point of intersection: (5/8, 5/2) Square both sides of the first equation and merge it with the second equation to form a quadratic equation:- 4x2-5x+25/16 = 0 Solving the above using the quadratic equation formula gives x as having two poitive roots of 5/8 and substituting this into the linear equation gives y a value of 5/2.
What quadratic equation is the answer for -5?
x2 + 10x + 25 = 0
Simplify 2t squared plus 8t plus 5 equals 0?
2t2+8t+5 = 0 The expression in this quadratic equation is not so simple to factorise because 5 is a prime number which has only two factors (itself and one) but we can get a near enough solution by using the quadratic equation formula. Using the quadratic equation formula gives the solution as: t = - 0.7752551286 or t = - 3.224744871
What is the rate of change in the equation x equal 9?
0. Differentiation of a constant gives f'(x)=0.
What are the solutions to the equation of 2x squared plus 5x -k equals 0 showing work?
You can use the quadratic equation for this one. Set a = 2, b = 5, c = -k.Another Answer:-Using the discriminant of b^2-4ac = 025-4(-2k) = 0 => 25+8k = 0 => k = -25/8 or -3.125So: 2x^2+5x-(-3.125) = 0Using the quadratic equation formula: x has equal values of -5/4 or - 1.25
How do you solve for x X2 plus 3x plus 1 equals 0?
x2+3x+1 = 0 Using the quadratic equation formula gives you: (x+2.618033989)(x+0.3819660113) = 0 So: x = -2.618033989 or x = -0.3819660113
How do you solve v2 - 25?
-23
How do you solve for x using a quadratic equation?
For an equation of the form ax² + bx + c = 0 you can find the values of x that will satisfy the equation using the quadratic equation: x = [-b ± √(b² - 4ac)]/2a
What is the quadratic equation with the solutions -1 an 5?
The equation must have roots of x = -1 and x = 5 So: x + 1 = 0 and x - 5 = 0 Therefore: (x + 1)(x - 5) = 0 Expanding the brackets gives the equation: x2 - 4x - 5 = 0
What is the equation of a circle centered at the origin with a radius of 5cm?
x2 + y2 = 25 A circle with centre (xo, yo) and radius r has equation: (x - xo)2 + (y - yo)2 = r2 So with centre the origin (0, 0) and radius 5 cm, the circle has equation: (x - 0)2 + (y - 0)2 = 52 ⇒ x2 + y2 = 25
