3*(2+4)-1 = 17
4*4*2+2*3
(1+4) x (2 x 3)
How about: 2*(1+3+4) = 16
20 = (3 + 2) x (4 x 1) = 5 x 4
4x4x3+2
By the uniqueness of numbers, the only number for 1234 is 1234 itself.
3*(2+4)-1 = 17
4*4*2+2*3
(3 x 4) + (2 - 1)
(1+4) x (2 x 3)
How about: 2*(1+3+4) = 16
2^(4+1)-3
18 = (4 × 3) + (2 × 1)
17 = (4+2)*3 - 1
20 = (3 + 2) x (4 x 1) = 5 x 4
3 x 4 x (2-1) OR 2 x 4 + 1 + 3