(3 x 4) + (2 - 1)
Yes, as long as the two nonzero numbers are themselves rational. (Since a rational number is any number that can be expressed as the quotient of two rational numbers, or any number that can be written as a fraction using only rational numbers.) If one of the nonzero numbers is not rational, the quotient will most likely be irrational.
A prime number is a number which can only be divided by itself and 1. All even numbers are not prime numbers (except for 2) Only odd numbers, try dividing the number with a few possible other numbers, if you can't find any whole answers, than that number is a prime number.
no. 2 is the only even prime number. Prime numbers are numbers that only have two factors; one and itself. E.g. The number 7 only has two factors- 1x7=7. 2 is a factor of all even numbers, therefore no other even numbers are prime. They are composite. 2, however, is a prime number, as it's only factors are itself (2) and 1.
'0' is the only whole number that is not a counting number. Negative integers do not belong to whole numbers.
By the uniqueness of numbers, the only number for 1234 is 1234 itself.
17 = (4+2)*3 - 1
4 dvided by 2 minus 1 times 3
Since the order of the digits does not matter there are only five combinations: 1234, 1235, 1245, 1345 and 2345.
3*(2+4)-1 = 17
4*4*2+2*3
(3 x 4) + (2 - 1)
It can be: 2*3+4+1 = 11
(1+4) x (2 x 3)
How about: 2*(1+3+4) = 16
2^(4+1)-3
18 = (4 × 3) + (2 × 1)