Take the first few points.
y = x^3
x | y
--------
0 0
1 1
2 8
3 27
4 64
5 125
Don't forget there is also a negative side! Since the exponent is odd the y values will be negative! So it looks like:
y
a
x
i
s
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/
/ x axis
/
/
|
|
|
It would be less steep
Assuming you're talking about transforming graphs, you mirror the graph along the line y = -x.
x=y+2 y=x-2 The y value at the x axis (x=0) will be -2, so graph (0, -2). Let's calculate a few more points by varying x and calculating y: if x=2, y=2-2=0 (2, 0) similarly: (1, -1) (5, 3) Graph those points, then draw a line connecting them all. That's the graph of x=y+2.
3
No translation will invert a quadratic graph.
A cubic function.
y equals x-4 plus 2 is the same as y = x-2. You just translate the graph of y=x, 2 units to the right, OR 2 down.
y=x+1 there for answer is 2
First, reflect the graph of y = x² in the x-axis (line y = 0) to obtain the graph of y = -x²; then second, shift it 3 units up to obtain the graph of y = -x² + 3.
The graph shifts downward (negative y) by 9 units.
3
1
Yes, y = -x3+1 is a function. You can graph it and see that it passes the vertical line test. See related link, below.
solve for y so if x + y = 0 then y = -x
y=x-2
It is zero.
You subtract X from both sides, in which u get y=x-4; u should be able to graph that