It would be less steep
Assuming you're talking about transforming graphs, you mirror the graph along the line y = -x.
x=y+2 y=x-2 The y value at the x axis (x=0) will be -2, so graph (0, -2). Let's calculate a few more points by varying x and calculating y: if x=2, y=2-2=0 (2, 0) similarly: (1, -1) (5, 3) Graph those points, then draw a line connecting them all. That's the graph of x=y+2.
3
The given equation y=3+x is a linear line with the slope of 1 and y-intercept of 3.
A cubic function.
y equals x-4 plus 2 is the same as y = x-2. You just translate the graph of y=x, 2 units to the right, OR 2 down.
y=x+1 there for answer is 2
First, reflect the graph of y = x² in the x-axis (line y = 0) to obtain the graph of y = -x²; then second, shift it 3 units up to obtain the graph of y = -x² + 3.
The graph shifts downward (negative y) by 9 units.
3
Yes, y = -x3+1 is a function. You can graph it and see that it passes the vertical line test. See related link, below.
1
solve for y so if x + y = 0 then y = -x
y=x-2
It is zero.
The graph of y = x - 8 is a straight line. The slope of the line is 1, and it intersects the y-axis at the point y = -8.