Take the first few points.
y = x^3
x | y
--------
0 0
1 1
2 8
3 27
4 64
5 125
Don't forget there is also a negative side! Since the exponent is odd the y values will be negative! So it looks like:
y
a
x
i
s
|
/
/ x axis
/
/
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|
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It would be less steep
Assuming you're talking about transforming graphs, you mirror the graph along the line y = -x.
x=y+2 y=x-2 The y value at the x axis (x=0) will be -2, so graph (0, -2). Let's calculate a few more points by varying x and calculating y: if x=2, y=2-2=0 (2, 0) similarly: (1, -1) (5, 3) Graph those points, then draw a line connecting them all. That's the graph of x=y+2.
3
No translation will invert a quadratic graph.