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ordered pair
An ordered pair that has a negative x-coordinate and a positive y-coordinate (-,+) would be plotted in which quadrant?
The rule for a set of ordered pairs is the statement that states the relationship of of a certain value to another value.For example:given the set of ordered pair { (1,2) , (3,4) , (5,6) , (7,8) }we notice that the value of y is increased by 1 as the value of x varies.For instance, in the first ordered pair which is (1,2) where 1 is x and 2 is y such that (x,y), 1 increased by 1. In other words, x is increased by 1.So we say that the rule of the ordered pair is:{(x,y) | y = x + 1 }read as "The set of ordered pairs such that y is equal to x plus one"
No, the origin is the point where the x-axis and y-axis meet in the coordinate plane. The x value of an ordered pair is called the abscissa (the y value is called the ordinate).
Hello! i think it would be -6... thanks! -Jim
Slope-Intercept Form is y=mx+b. m=slope and b=y-intercept. The y and x stand for the x and y coordinates in an ordered pair (x,y).
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-3
The symbol for an ordered pair is (x,y).
AnFind the midpoint of the segment below and enter its coordinates as an ordered pair. (-3,4) (-3,-2)
y=mx+b is commonly referred to as slope-intercept form. It is one way to show a linear equation, where: y = the y part of an ordered pair, x = the x part of an ordered pair, m= the slope of a line-rise over run is slope, so your numerator is how many you go up, and your denominator is how many you go over-you draw these dots and then connect them, and b = the y intercept-that is, the ordered pair where the line crosses over the y axis.
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(1,2)
Assume we want to find the ordered pair after 90° counterclockwise rotation. From (x,y), we have (-y,x). If we want to find the ordered pair after 90° clockwise rotation, then from (x,y) we have (y, -x)
If the reflection is over the x value, the x-value does not change.
1