-3
y = 6x-9
A y-intercept is the point in which the given line meets with the line x=0. Therefore, make x equal to zero and you find the y-intercept of a line.
y = 6(0)-9
y = 0 - 9
y = -9
When x = 0, y = -9, so the ordered pair that is the y-intercept is (0, -9).
16
y = x - 7 x + y = 5 Substituting for y in the second equation, x + (x - 7) = 5 or 2x = 12 so that x = 6 Then, from the first equation, y = 6 - 7 = -1 So, (x, y) = (6, -1)
Solve the equation for x, and enter your answer in the box below.
Use the substitution method to solve the system of equations. Enter your answer as an ordered pair.y = 2x + 5 x = 1
2x + 14 = 0Subtract 14 from each side of the equation: 2x = -14Divide both sides of the equation by 2: x = -7You can also obtain solutions to equations by visting wolframalpha.com. Enter solve 2x+14=0, for example. You can click on the 'step-by-step' button to see how the equation was solved.
(-4,3)
(-4, -6)
16
2y + 2x = 20 y - 2x = 4 Add the two equations: 3y = 24 so that y = 8 Substitute this value of y in the second equation: 8 - 2x = 4 then 4 = 2x so that x = 2 Thus the ordered pair (y,x) = (8,2)
(0,7)
UndefinedImproved Answer:-The straight line equation is: y = 2x
-2
(x+7)2+(y+5)2 = 16 Centre of circle: (-7, -5) Radius: 4
I think this means (x+7)squared + (y-5)squared =4squared, which represents a circle centred at -7,+5
y=13x
y=x
y = x - 7 x + y = 5 Substituting for y in the second equation, x + (x - 7) = 5 or 2x = 12 so that x = 6 Then, from the first equation, y = 6 - 7 = -1 So, (x, y) = (6, -1)