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Q: How do you integrate open bracket x plus 1 close bracket cosx?

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(x-2)(x+2)= x2+2x-2x-4= x2-4

(:)+< Open bracket, :, close bracket, plus, < less then

7C MINUS bracket open c plus 2 bracket close equals 7c minus c minus 2 equals 6c minus 2

you first solve the inside of the bracket and then do the inside answer with the outside numbers.

2(2*1) = 2(2) = 4

-(3x-4) = -3x + 4

sure... I bet lots of people can simplify this... How 'bout 5x sq -15

:) colon then close bracket :( colon then open bracket :D colon then D XD X then D Those are just a few!

2(2*4-5)+6 = 12

I think I'm answering my own quezstion here but hey. Am I right in saying that (x+0)(x+1) Factorises to x2+ x? I think I am.

sounds like 21: (7 x 2) is 14, plus 7 is 21

-3(2x + 1)(4 + 3x) = -3[8x + 6x2 + 4 + 3x] = -3[6x2 + 11x + 4] = -18x2 - 33x - 12.

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