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Consider newtons equation: v = (a * t) + u, and you need to isolate a because you have the values for v, t and u and need to find a, first subtract u from both sides, gives v - u = (a * t) + u - u, the + u - u cancel leaving v - u = a * t, so essentially you've moved the u from one side to the other, then you would divide both sides by t, the t's would cancel out on the right side, leaving

(v - u) / t = a, essentially you've moved the t over to the other side, now a is isolated and can be calculated.

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Consider x + 4 = 10: find x (isolate x), subtract 4 from both sides, leaving

x + 4 - 4 = 10 - 4, the 4's cancel out on the left, leaving x = 10 - 4, so x = 6

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Q: How do you know what numbers to subtract from both sides?
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How do you find the unknown length of one side of a triangle when you know the perimeter and the length of the other two sides?

subtract the two sides that you know from the perimeter to get the unknown side.


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The equation y = 7x + 10 can be solved when we know that y = 3. Using basically algebra, the value of x can be determined, which is -1. Simply subtract 10 from both sides of the equation and then divide both sides by 7.


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subtract the two sides that you know from the perimeter to get the unknown side.


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How do you get the variable alone in a equation?

To explain this, I'll use the example equation: 3x+8=5x-4 To get the variable alone, you must add, subtract, multiply, or divide both sides by the correct numbers to get x on one side. This is easier than it sounds. First, get x on one side. To do this, subtract both sides by 3x, which gives you: 8=2x-4 Next, you must get all the constants on the other side. To do this, add 4 to both sides, giving you: 12=2x Finally, you have to remove the coefficient from x. To do that, divide both sides by 2, which gives you: 6=x Plug that back into your original equation, which gives you: 3(6)+8=5(6)-4 18+8=30-4 26=26 This is a true statement, so we know that we have the correct answer.


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