999 + (999/999) = 1000
9÷9+99 or 99+9÷(9)
9^2+9+9 +9/9 81+9+9+1=100
5
Every ten there is a nine in the ones place, therefore there are 100 nines in the ones place.Every hundred there are 10 nines in the tens place, therefore add 10 * 10 nines. eg 90, 91, 92, 93, ... in the tens placeEvery thousand there are 100 nines in the hundreds place, therefore add 100 nines.Total is 300.
999 + (999/999) = 1000
Ninety nine divided by nine equals eleven
That depends what those nine numbers are. If the numbers are 992, 1, 1, 1, 1, 1, 1, 1, and 1, then it is easy.If the numbers are all 9s, then it can be written 999 + (999 / 999) = 1000.
You could have one No. 9 or a handful of No. 9s
Nine of them
9.99999999
wait not the discription srry
111 of them with a remainder of 1
9 + (9/9) = 10(99/9) - (9/9) = 10
You have to combine equal terms. -5r-9s+9r+3s-6 = -5r+9r-9s+3s-6 = 4r-6s-6
1 ns (nanosecond) = 10-9s 1s / 10-9s = 109 109 = 1000 000 000 1 second = 1000 000 000 ns (nanosecond)
No. But if the 9s go on for ever - the infinitely recurring decimal fraction - will equal 1.