72 holes = 5 degree spacings (5 x 72 = 360) The centre-to-centre distance of the holes is c = 60.4129mm. You can either mark out the holes using a protractor at 5 degree spacings, or you must calculate the distance 'c' given above. c = sqrt ( 2 x r2 - ( 2 x r2 x cos a )) r = radius = 1385/2 = 692.5mm a= angle = 5 degrees
It is the radius from the centre to the circumference or the diameter passing through the centre to both sides of the circumference
Assuming you know the location of the center of the circle, to divide a circle into thirds, do the following:mark a point on the circumference and, using a protractor, mark 120 degreesthen repeat for the final markA line from the mark on the circumference to the center will show an angle of 120 degrees.
"Flat shape" is a broad description that can be categorized into several more specific descriptions. For example, polygons, circles, and the outline of an irregular object such as a giraffe can all be described as flat shapes. For polygons, which are closed shapes with 3 or more straight sides, the perimeter is the sum of the lengths of the individual sides. The perimeter of a circle is pi (3.14) times the length of the diameter of the circle. A diameter is any line that connects two points on the edge of the circle and passes through the center. Other shapes have more specific perimeters, but in general, a flat shape's perimeter is the length of string that would be required to fully mark the outline of the shape.
Let us assume you have a circle drawn with the center identified. Then draw one straight line through the center. Measure the length of the line bound by the intercepts of the straight line with the circumference of the circle. The line segment is the diameter. Another case would be that you have a circle drawn with no center marked. Draw one straight line through the circle. Use a compass to draw the perpendicular bisector of the line segment bound by the intercepts of the straight line with the circumference of the circle toward the inner circle (the center of a circle cannot lie outside the circle!). Repeat drawing another (different) straight line through the circle and finish with a perpendicular bisector. The two bisectors will intercept at the center of the circle. Then you can proceed the same way as described in the first paragraph above. Hint to draw a perpendicular bisector of a line segment: take one end of the compass, pivot the point at one end of the line segment and mark an arc with the other end on both sides of the line. Move the compass and pivot one point at the other end of the line segment. Mark an arc with the other end on both sides of the line. If the procedure is done correctly, the two arcs, one from each end, should intercept on one side of the line. There is another intercept of the two arcs on the side of the line. Connect the two arc-intercepts with a straight line. Convince yourself that the line bisects the straight line at a right angle. This last line is the perpendicular bisector of the original line (The first and last lines form the perpendicular bisector of one another). ===================
72 holes = 5 degree spacings (5 x 72 = 360) The centre-to-centre distance of the holes is c = 60.4129mm. You can either mark out the holes using a protractor at 5 degree spacings, or you must calculate the distance 'c' given above. c = sqrt ( 2 x r2 - ( 2 x r2 x cos a )) r = radius = 1385/2 = 692.5mm a= angle = 5 degrees
72 The diameter is the full length from left to right and the radius is taken from a central point, in this cas at the 72 mark.
Draw a diameter on the circle from A to B and mark the midpoint, C (center of the circle). Mark the midpoint, D, of one of those radii (halfway between center and edge). Draw a perpendicular line to the diameter from D to the two edges of the circle, E and F. Draw radii from E to C and F to C. Lines AC, EC, and FC mark the three equal parts of a circle.
It is the radius from the centre to the circumference or the diameter passing through the centre to both sides of the circumference
simple option: take a string, wrap it around the tube, cut off extra, measure the string. Divide by 3, use a ruler to mark the 3 spots on the string, wrap back around tube, and transfer the dots to the tube. DRILL! Accurate option: find circumference of tube. (you can find this by measuring the diameter of the tube, multiply that by PI) divide by 3, mark a starting point, drill holes offset by your length.
Construct a circle with a 4.5 radius. The circle's circumference is 360 degrees. So mark out 3 by 120 degrees on the circumference and join them to the centre of the circle which will divide the circle into three equal parts.
The center circle is 10 yards in radius. The penalty arc is 10 yards from the penalty mark. The corner arcs are all 1 yard from their corresponding corner. A semi-circle is exactly one half of a circle and there aren't any on the a football pitch.
the "r" in a circle is called "Radius". It the same as half of the diameter. ---- A capital R in a circle is a registration mark. It is used to signify registration of a trademark and is placed on a product to signify ownership of the rights to that product.
-- Draw a circle. -- Put a mark at the center, and draw a line across the whole circle through the center. -- Measure the length of the curved line all around the circle. (called the "circumference" of the circle) -- Measure the length of the straight line across the circle. (called the "diameter" of the circle) If you divide the circumference by the diameter, the result is 'pi'. It doesn't matter how big or how small the circle is. The result is always the same.
JULY 29, 1961, His name is Mark Holmes not Mark Holes
If Mark makes a circle, that circle would have a circumference of 12 inches. The formula for circumference is pi times diameter, so the circumference divided by pi will give you the diameter of 3.82 inches. Divide this by 2 to get the radius of 1.91 inches. Area of a circle is pi times the radius squared. 1.91 squared is 3.6481. Multiply this by pi to get 11.46 square inches of area inside the circle. A circle is always the most efficient use of space possible given a fixed perimeter. If Mark makes a square with equal sides where all sides are 3 inches, the area would be 9 square inches. 3 X 3 = 9
Short instructions:Construct the diameter of the circle at the tangent point Construct a line at right angles to the diameter at the tangent point. this is a tangent to the circle at that point.Detailed instructions with compass and straight edge:Given: circle C with a point T on the circumference Sought: Tangent to C at TFind the center circle CPlace the needle of the compass on the (circumference of) circle C (anywhere), draw a circle [circle 1] (I think circle 1 has to be smaller than twice the diameter of circle C).Without changing the compass size, place the needle of the compass on the intersection of circles C and circle 1, draw a circle (circle 2)Without changing the compass size, place the needle of the compass on the other intersection of circles C and circle 1, draw a circle (circle 3)Connect the intersections of circle 1 and circle 2 (one is outside and one inside circle A) this we call [ line 1]Connect the intersections of circle 2 and circle 3 (also here one is outside and one inside C) [line 2]The intersection of line 1 and Line 2 is [O]. This is the center of circle CDraw a line [line 3] from [O] through [T] and beyondConstruct the diameter of the circle at [T] (the point for the tangent) and extend it beyond the circumference of circle C With your compass needle at [T] mark off equal distances on [line 3] inside and outside circle C. We call these points [4] & [5]Increase the compass size somewhat and with the needle at [4] draw a circle [circle 4]Without changing the compass draw [circle 5] centered on [5]Construct a line perpendicular to line 3 at [T]The line through the intersections of circle 4 and circle 5 is the sought tangent at [T]Note: although the instructions say "draw a circle" often it is sufficient to just mark a short arc of the circle at the appropriate place. This will keep the drawing cleaner and easier to interpret.