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Factor 5y3 - 125y?
5y3 - 125y = 5y(y2-25) = 5y (y+5)(y-5)
What is the factor of 27x2-75y2 using more than one method?
3(3x - 5y)(3x + 5y)
How do you factor out x squared plus 8xy plus 15y squared?
x2 + 8xy + 15y2 = (x + 3y) (x + 5y)
How do you factor 512x3 plus 125y3?
(8x + 5y)(64x^2 - 40xy + 25y^2)
What algbraic expression is a product with a factor of 5?
One such expression is 5n
Factor 5y3 - 125y?
5y3 - 125y = 5y(y2-25) = 5y (y+5)(y-5)
What is cube of binomial mean?
The cube of a binomial is the cube of two terms separated by an addition or subtraction sign, such as (2a + 3b) or (ab - cd).For example, (2x - 5y)3 = 8x3 - 40x2y + 50xy2 - 20x2y + 100xy2 - 125y3.The detailed method of expanding this binomial is : (2x - 5y)3 = (2x - 5y)(2x - 5y)(2x - 5y) = (4x2 - 20xy + 25y2)(2x - 5y) = 8x3 - 40x2y + 50xy2 - 20x2y + 100xy2 - 125y3
How do you factor 12y to the third power minus 30y squared plus 12y?
12y3 - 30y2 + 12yFactor out a y:y(12y2 - 30y + 12)Factor out a 6:6y(2y2 -5y + 2)Factor 2y2 - 5y + 26y(2y - 1)(y - 2)
How do you factor 25y squared minus 4?
(5y - 2)(5y + 2)
How do you factor 5y-65xy?
5y - 65xy '5' is a common factor both numbers. Hence 'take it out'. 5(y - 13xy) 'y' is a common factor to both terms, so take it out too!!!! 5y(1 - 13x) Done Factored!!!!!
What is the greatest common factor of 20y3 5y2 45y?
The GCF is 5y.20y3 = (5y)(4y2)5y2 = (5y)(y)45y = (5y)(9)
How do you factor a polynomial 25w2-64?
(5y + 7w)(5y - 7w)
Is it possible to find the conjugate of a binomial with a division or multiplication sign in the middle?
No
Factor expression 16x2 - 25y2?
Remember both 16 & 25 are squared numbers. 16 = 4^2 & 25 = 5^2 Hence we can write (4x)^2 - (5y)^2 Remember two squared terms with a NEGATIVE Between them will factor. ( 4x - 5y)(4x + 5y) Note the difference signs. NNB Two squared terms with a positive (+) between them DOES NOT factor.
How do you factor 2x-10y?
2(x - 5y)
What is the factor of 27x2-75y2 using more than one method?
3(3x - 5y)(3x + 5y)
How do you factor y to the sixth power minus 125y cubed?
y to the six is common, so it becomes y^3(y^3 - 125). Then we use difference of cubes ((a-b)(a^2 - 2ab + b^2)), so it becomes y^3(y-5)(y^2 + 5y + 25). Since we cannot factor out that last quadratic part, this concludes the factoring process and we end up with that last line as our answer.
