A) Subtract 6 from 48. If the result less than 6 or 0 you made a mistake. Result is 42. Hence start a counter with a value of 1.
B) Subtract 6 from 42. If the result less than 6 or 0 you made a mistake. Result is 36. Hence increment the counter by 1. Now counter value is 2.
C) Subtract 6 from 36. If the result less than 6 or 0 you made a mistake. Result is 30. Hence increment the counter by 1. Now counter value is 3.
D) Subtract 6 from 30. If the result less than 6 or 0 you made a mistake. Result is 24. Hence increment the counter by 1. Now counter value is 4.
E) Subtract 6 from 24. If the result less than 6 or 0 you made a mistake. Result is 18. Hence increment the counter by 1. Now counter value is 5.
F) Subtract 6 from 18. If the result less than 6 or 0 you made a mistake. Result is 12. Hence increment the counter by 1. Now counter value is 6.
G) Subtract 6 from 12. If the result less than 6 or 0 you made a mistake. Result is 6. Hence increment the counter by 1. Now counter value is 7.
H) Subtract 6 from 6. If the result is not 0 you made a mistake. Result is 0. Hence increment the counter by 1. Now counter value is 8. Since we have nothing more to subtract from stop the process. The last value of the counter was 8 and so the quotient is 8.
33*3=99 3*33=99
Professor Layton? 41268 - 7935 (or 41286 - 7153)
4.5
1.125
the answer is unknown error
110 divided by 2
33*3=99 3*33=99
123-45-67+89??
(5 divided by 5) + (5 divided by 5) = 2
Professor Layton? 41268 - 7935 (or 41286 - 7153)
16
5 divided by 5, plus 5
4.5
54
1.125
288 - without using a calculator ! 288/4=72
28 divided by 7 = 4