Add 1 hundred's place block to 20 ten's place blocks to 15 one's place blocks.
(1 X 100) + (20 X 10) + (15 X 1) = 100 + 200 + 15 = 315 and you used 36 blocks.
(2x100)+(15x4)+(7x1)=200+60+7=267
How do you draw 2.6, 0.47, and 1.05 with base ten blocks ??
3 tens 1 tens 5 ones
No. In that case it is 0.0
No, it's impossible. If you did it with hundredths blocks then it would be fair.
(2x100)+(15x4)+(7x1)=200+60+7=267
4*100 + 8*10 + 1
How do you draw 2.6, 0.47, and 1.05 with base ten blocks ??
To model multiplying decimals using base ten blocks, you can represent each decimal as a fraction of the blocks. For example, if you are multiplying 0.3 by 0.4, use 3/10 of a flat (representing 0.3) and 4/10 of a flat (representing 0.4). Arrange these sections to show that the product is found by taking the area of the overlapping blocks. In this case, the product would be 0.12, represented by the smaller blocks formed from the overlap.
3 tens 1 tens 5 ones
No, it's impossible. If you did it with hundredths blocks then it would be fair.
No. In that case it is 0.0
(-3) -8- (-7)=
No, it's impossible. If you did it with hundredths blocks then it would be fair.
no, it's impossible unless your using the hundredths place.
To represent the number 4200 using place-value blocks, you would need 4 thousands blocks (for the 4000), 2 hundreds blocks (for the 200), and no tens or ones blocks. Therefore, the least number of place-value blocks needed is 6. This includes 4 blocks for the thousands and 2 blocks for the hundreds.
The Hayseeds' Back-blocks Show was created on 1917-11-05.