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Well, darling, to solve 4y x 2y, you simply multiply the numbers together and then multiply the variables together. So, 4 times 2 is 8, and y times y is y^2. Therefore, the answer is 8y^2. Easy peasy, lemon squeezy!
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What is the answer to X2 plus 13xy plus 36y2?
If by "What is the answer to", you mean "How do you factor", then we can solve it as follows: x2 + 13xy + 36y2 = x2 + 4xy + 9xy + 36y2 = x(x + 4y) + 9y(x + 4y) = (x + 9y)(x + 4y)
How do you solve 2y equals 4x plus 4?
2y = 4x + 4y = 2x + 2
How do you solve 4x - 4y plus 7 equals 15?
4x - 4y + 7 = 15to get it into y-intercept form do this...4x -4x - 4y + 7 - 7 = 15 - 7 - 4x-4y = 8 - 4x-4y / -4 = (8 / -4) + (-4x / -4)y = x + 2you did not give any values to plug in so this is as best an answer i can give
How do you solve y2 - 3y plus 2 plus 3y - 4y - 5?
I don't know whether it's y^2-3y+2+3y-4y-5 or 2y-3y+2+3y-4y-5, so I'll do both.y^2-3y+2+3y-4y-5y^2+(-3y+3y-4y)+(2-5); group them togethery^2+(-4y)+(-3)y2-4y-3OR2y-3y+2+3y-4y-5(2y-3y+3y-4y)+(2-5); group them together(-2y)+(-3)-2y-3
Solve this equation using subtitution x equals 4y and 3x-2y equals 20?
3x - 2y = 20 Substitute x = 4y into this equation: 3(4y) - 2y = 20 ie 12y - 2y = 20 10y = 20 so that y = 2 and then x = 4y gives x = 2*4 = 8
How do you factor 3x3-x2y plus 12x-4y?
3x3 - x2y + 12x - 4y = x2*(3x - y) + 4*(3x - y) = (x2 + 4)*(3x - y)
Solve the equation y' plus x2y equals x2?
(2x)ysquared
How do you solve 4y plus x equals 8?
How do you solve 4y plus x equals 8
How do you solve x 40-4y?
Assume the expression is x = 40 - 4y, and assume we want to solve for y. Rearrange the terms to get: x - 40 = -4y y = -¼(x - 40)
Solve for y in the equation 4y plus 7 equals 19?
4y + 7 = 19 ∴ 4y = 12 ∴ y = 3
please solve these for me3x+4y?
daïras
What is the answer to -x-4y-6?
2
How do you solve a linear equality with two unknowns?
Isolate one of the variable using inverse operations. Then solve. Example: 2x + 4y = 0 --subtract 4y>> 2x = -4y --divide by -4>> -1/2x = y --plug in your variable -->>
How do you solve x-40?
Assume the expression is x = 40 - 4y, and assume we want to solve for y. Rearrange the terms to get: x - 40 = -4y y = -¼(x - 40)
How do you solve x squared minus 2x minus 4y squared minus 4y?
The answer to x2 - 2x - 4y2 - 4y =(x - 2y)(x - 2y - 2)
How do you solve 4y -2 8y-5?
12y-7
11x - 4y equals -28?
Does it say solve for y?
