The answer to x2 - 2x - 4y2 - 4y =
(x - 2y)(x - 2y - 2)
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This is a difference of two squares, which factorises to: (3x - 4y)(3x + 4y)
(5x - 2y)(5x + 2y)
x = 2 so x squared = 4 and 2x squared = 2 times 4 = 8; y = 4 so xy = 2 times 4 = 8 and 3xy = 3 times 8 = 24; y squared = 4 times 4 = 16 and 4y squared = 4 times 16 = 64; so 8 + 24 - 64 = 32 - 64 = -32
7(3y-2)-(-4y+9)
2x + 4y = 16 <=> 2x + 4y - 16 = 0 2x - 4y = 0 2x - 4y = 2x + 4y - 16 -8y = -16 y = 2 Substituting the known value for y in either of the original equations enables x to be determined. 2x + (4*2) = 16 : 2x = 16 - 8 : x2x = 8 : x = 4 2x - (4*2) = 0 : 2x - 8 = 0 : 2x = 8 : x = 4. The ordered pair satisfying both equations is (4,2)