6x/2 = 10
6x = 10 x 2 (when taking the 2 to the RHS it is multiplied over because of the division on the LHS)
6x = 20
x = 20/6 (when taking the 6 to the RHS it id divided over because of the multiplication on the LHS)
x = 4
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Here, let me try:
6x/2 = 10
Reduce the fraction on the left to lowest terms.
Divide numerator and denominator by 2:
3x = 10
Divide each side of the equation by 3:
x = 10/3
x = 31/3
40=4-6x 40-(4)=4-6x-(4) 36=-6x -6=x
6x + 8 = 13, 6x = 13 - 8, 6x = 5, x = 5/6
-6x + 12y = -102 -6x = -12y - 102 x = 2y + 17
6x - 7 = 5Add 7 to each side:6x = 12Divide each side by 6:x = 2
16x+9 without the rest of the equation, what this equals, I can't solve
If 6x + 10 = 11x , then x=2.
-4x-6x = -20 -10x = -20 Divide both sides by -10 rembering that a minus divided into a minus the result is positive: x = 2
6x-20 = 8x 6x-8x = 20 -2x = 20 x = -10
6x-3x =6 3x=6 so 6 divided by 3 = 2
6x + 3 = -7 -5x 6x + 5x = -7 -3 11x = -10 x = -10/11
x=-8
4x=-10 x=-2.5
you multiply it
6x-5 = 7, 6x = 7+5, 6x = 12, x = 2
I'm an orange!
To solve for two unknown variables (x and y) you need two independent equations, one is not enough.
-10 = 6x - 16, or 16 - 10 = 6x, or x = 1.