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You cannot solve this statment as there is nothing to equate to it.

However, it will factor.

9 - 4z^2

First we note that both '9' and '4' are squared numbers.

9 = 3^(2) & 4 = 2^(2)

So we can re-write the statement as

3^(2) - (2z)^(2)

Note that it now has two squared terms with a negative between them . This will factor to

3^(2) = (2z)^2 = ( 3 - 2z_)(3 + 2z) NOTE the different signs.

NB Two squared terms with a positive(+) between them will NOT factor.

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lenpollock

Lvl 16
1y ago

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9-4z2 = (3-2z)(3+2z)

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Wiki User

14y ago
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Q: How do you solve 9-4z2?
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