105
y-b/x=m
It depends on which variable you wish to solve for.
N=l-m
m-15=3 m-15+15=3+15 m=3+15 m=18
m= -3
-8m = 48 m = 48/-8 m = -6
m/-6 + 6 = 41 subtract 6 from each side m/-6 = 35 multiply both sides by -6 m = -210
Y = mX + 6 Y - 6 = mX (Y - 6)/X = m ==============If you had values you could get the integer that is m
105
6m = 42 Divide both sides by 6: m = 7
In your question you have two equations. They are... m + n = 1000 Equation (1) 0.05 + 0.06n = 57 Equation (2) It is a rule of thumb that if you have two equations and two unknowns (the unknowns in this case are "m" and "n") you can solve for them. Also remember if you have three euqations and three unknowns you can solve for them.. four euqations four unknowns... etc.. Ok first take the 2nd equation and solve for "n" 0.05 + 0.06n = 57 0.06n = 56.95 n= 949 and 1/6 Now that you have "n" you can put it into the 1st euqation and solve for "m" m + (5695/6) = 1000 m = 50 and 5/6 Therefore you answers are... n=949.16666 or 949 1/6 or 5695/6 m=50.83333 or 50 5/6 or 305/6
how can i solvev 10=7-m
m=16, n=2
-12=m+4 -16=m
m-12=25. m=37
54